按月份名称对查询输出进行排序

Question

我正在尝试使用SQL查询从Excel中提取值，但是我一直在努力的是按照月份的顺序对月份进行排序。现在，该表格正在按A-Z排序，我尝试使用DATEPART，但是由于遇到了Int16错误而不能非常成功。

Select F1,
SUM(F2),
ROUND(SUM(REPLACE(F3, ',', '.')), 2),
ROUND(SUM(REPLACE(F4, ',', '.')), 2)
FROM [Sheet1$]
WHERE F1 IN ('January', 'February', 'March', 'April', 'May', 'June',
'July', 'August', 'September', 'October', 'November', 'December')
GROUP BY F1;

这是有效的查询，但结果是：

我也乐意接受任何可以提高查询速度的建议，因为该文档非常大，大约有5万行，谢谢。

对于想知道最终查询是否有效的任何人：

Select F1,
SUM(F2),
ROUND(SUM(REPLACE(F3, ',', '.')), 2),
ROUND(SUM(REPLACE(F4, ',', '.')), 2)
FROM [Sheet1$]
WHERE F1 IN ('January', 'February', 'March', 'April', 'May', 'June',
'July', 'August', 'September', 'October', 'November', 'December')
GROUP BY F1
ORDER BY SWITCH(
F1='January', 1,
F1='February', 2,
F1='March', 3,
F1='April', 4,
F1='May', 5,
F1='June', 6,
F1='July', 7,
F1='August', 8,
F1='September', 9,
F1='October', 10,
F1='November', 11,
F1='December', 12
);

Answer 1

使用CASE表达式：

Select
  f1,
  SUM(f2),
  ROUND(SUM(REPLACE(f3, ',', '.')), 2),
  ROUND(SUM(REPLACE(f4, ',', '.')), 2)
FROM [Sheet1$]
WHERE F1 IN ('January', 'February', 'March', 'April', 'May', 'June',
             'July', 'August', 'September', 'October', 'November', 'December')
GROUP BY F1
ORDER BY
  CASE F1
    WHEN 'January' THEN 1
    WHEN 'February' THEN 2
    WHEN 'March' THEN 3
    WHEN 'April' THEN 4
    WHEN 'May' THEN 5
    WHEN 'June' THEN 6
    WHEN 'July' THEN 7
    WHEN 'August' THEN 8
    WHEN 'September' THEN 9
    WHEN 'October' THEN 10
    WHEN 'November' THEN 111
    WHEN 'December' THEN 12
  END;

或动态创建一个月表：

Select
  s.f1,
  SUM(s.f2),
  ROUND(SUM(REPLACE(s.f3, ',', '.')), 2),
  ROUND(SUM(REPLACE(s.f4, ',', '.')), 2)
FROM [Sheet1$] s
JOIN VALUES
(
  ('January', 1),
  ('February', 2),
  ('March', 3),
  ('April', 4),
  ('May', 5),
  ('June', 6),
  ('July', 7),
  ('August', 8),
  ('September', 9),
  ('October', 10),
  ('November', 11),
  ('December', 12)
) months(month_name, month_number) ON s.f1 = months.month_name
GROUP BY s.f1
ORDER BY months.month_number;

或创建真实的月份表。

Answer 2

您可以这样做：

order by datepart(mm, f1 + ' 1 2000')