我的8051项目有这个问题。我想用键盘输入数字并进行操作,并在16x2 LCD中打印它们,并使用8051微控制器打印结果。一切正常,我可以进行基本操作并查看结果。但是,当我按键盘上的字符时,LCD会打印两次字符。我看不出问题出在哪里。如果您能帮助我,我将非常高兴。谢谢。
#include <reg51.h>
void lcdcmd(unsigned char);
void lcddata(unsigned char);
void MSDelay(unsigned int);
void disp_num(float num);
int get_num(char ch);
void lcdinit();
char scan_key(void);
sfr ldata = 0xA0;
sbit rs = P3^7;
sbit rw = P3^5;
sbit en = P3^6;
sbit r0=P1^0;
sbit r1=P1^1;
sbit r2=P1^2;
sbit r3=P1^3;
sbit c0=P1^4;
sbit c1=P1^5;
sbit c2=P1^6;
sbit c3=P1^7;
void lcdinit(){
MSDelay(15000);
lcdcmd(0x30);
MSDelay(4500);
lcdcmd(0x30);
MSDelay(300);
lcdcmd(0x30);
MSDelay(600);
lcdcmd(0x38);
lcdcmd(0x0F);
lcdcmd(0x01);
lcdcmd(0x06);
lcdcmd(0x80);
}
int main (void)
{
while(1){
unsigned int k=0, m=0, n=0;
int k2, k1;
char key, key1;
unsigned char ch2,ch3;
lcdinit();
key = scan_key();
k2 = get_num(key); // sayiya cevirdik.
lcddata(key); // lcd de goruntule.
ch2 = scan_key();
lcddata(ch2);
key1 = scan_key();
k1 = get_num(key1);
lcddata(key1);
ch3 = scan_key();
lcddata(ch3);
lcdcmd(0x01);
switch(ch2)
{
case 'A':
disp_num(k1 + k2);
break;
case 'B':
disp_num(k2 - k1);
break;
case 'C':
disp_num(k2 * k1);
break;
case 'D':
disp_num(k2 / k1);
break;
}
return 0;
}
}
void lcdcmd(unsigned char value)
{
ldata = value;
rs = 0;
rw = 0;
en = 1;
MSDelay(50);
en = 0;
MSDelay(50);
}
void lcddata(unsigned char value)
{
ldata = value;
rs = 1;
rw = 0;
en = 1;
MSDelay(50);
en = 0;
MSDelay(50);
}
void MSDelay(unsigned int itime)
{
unsigned int i, j;
for(i = 0;i < itime; i++)
for(j = 0; j < 5; j++);
}
char scan_key()
{
unsigned char c;
c='s';
while(!(c=='0' && c=='1' && c=='2' && c=='3' && c=='4'
&& c=='5' && c=='6' && c=='7' && c=='8'
&& c=='9' && c=='+' && c=='-' && c=='#'
&& c=='$' && c=='*' && c=='/' ))
{
r0 = 0; r1 = 1; r2 = 1; r3 = 1;
if(c0==0 && r0==0){ lcddata('7'); MSDelay(100000); return c = '7';}
if(c1==0 && r0==0){ lcddata('8'); MSDelay(100000); return c = '8';}
if(c2==0 && r0==0){ lcddata('9'); MSDelay(100000); return c = '9';}
if(c3==0 && r0==0){ lcddata('A'); MSDelay(100000); return c = 'A';}
r0 = 1; r1 = 0; r2 = 1; r3 = 1;
if(c0==0 && r1==0){ lcddata('4'); MSDelay(100000); return c= '4';}
if(c1==0 && r1==0){ lcddata('5'); MSDelay(100000); return c= '5';}
if(c2==0 && r1==0){ lcddata('6'); MSDelay(100000); return c= '6';}
if(c3==0 && r1==0){ lcddata('B'); MSDelay(100000); return c= 'B';}
r0 = 1; r1 = 1; r2 = 0; r3 = 1;
if(c0==0 && r2==0){ lcddata('1');MSDelay(100000); return c= '1';}
if(c1==0 && r2==0){ lcddata('2');MSDelay(100000); return c= '2';}
if(c2==0 && r2==0){ lcddata('3');MSDelay(100000); return c= '3';}
if(c3==0 && r2==0){ lcddata('C');MSDelay(100000); return c= 'C';}
r0 = 1; r1 = 1; r2 = 1; r3 = 0;
if(c0==0 && r3==0){ lcddata('*');MSDelay(100000);return c= '*';}
if(c1==0 && r3==0){ lcddata('0');MSDelay(100000);return c= '0';}
if(c2==0 && r3==0){ lcddata('#');MSDelay(100000);return c= '#';}
if(c3==0 && r3==0){ lcddata('D');MSDelay(100000);return c= 'D';}
}
return 0;
}
int get_num(char ch) //convert char into int
{
switch(ch)
{
case '0': return 0; break;
case '1': return 1; break;
case '2': return 2; break;
case '3': return 3; break;
case '4': return 4; break;
case '5': return 5; break;
case '6': return 6; break;
case '7': return 7; break;
case '8': return 8; break;
case '9': return 9; break;
}
return 0;
}
void disp_num(float num) //displays number on LCD
{
unsigned char UnitDigit = 0; //It will contain unit digit of numb
unsigned char TenthDigit = 0; //It will contain 10th position digit of numb
unsigned char decimal = 0;
int j;
int numb;
j=(int)(num*10);
numb=(int)num;
TenthDigit = (numb/10); // Findout Tenth Digit
if( TenthDigit != 0) // If it is zero, then don't display
lcddata(TenthDigit+0x30); // Make Char of TenthDigit and then display it on LCD
UnitDigit = numb - TenthDigit*10;
lcddata(UnitDigit+0x30); // Make Char of UnitDigit and then display it on LCD
MSDelay(2000000);
}
答案 0 :(得分:0)
我通过从此处删除lcddata()函数解决了探针问题:
key = scan_key();
k2 = get_num(key); // sayiya cevirdik.
lcddata(key); // lcd de goruntule.
ch2 = scan_key();
lcddata(ch2);
key1 = scan_key();
k1 = get_num(key1);
lcddata(key1);
ch3 = scan_key();
lcddata(ch3);
lcdcmd(0x01);
我不明白您想在scan_key()函数中对while()说什么,它在模拟中效果很好。但是,现在我想为此操作的结果创建20秒的延迟,我使用MSDelay()函数进行了尝试,但没有任何改变。
编辑:抱歉,现在我在while()中意识到了错误。那是一个巨大的错误,我会解决的,谢谢大家。