Question

错误将文件上传到我选择的文件夹时，会出现以下错误。

由于我是不熟悉Flask的人，因此无法捕获错误。

未找到

在服务器上找不到请求的URL。如果您手动输入网址，请检查拼写，然后重试。

app.py

/**
 * Custom credentials to validate the status of user.
 */
public function credentials(Request $request)
{
    return [
        'email'     => $request->email,
        'password'  => $request->password,
        'is_active' => '1'
    ];
}

upload.html

import os
#import magic
import urllib.request
#from app import app
from flask import Flask, flash, request, redirect, render_template
from werkzeug.utils import secure_filename
app = Flask(__name__)

#app.config['UPLOAD_FOLDER'] = UPLOAD_FOLDER
UPLOAD_FOLDER = '/static'
ALLOWED_EXTENSIONS = set(['txt', 'pdf', 'png', 'jpg', 'jpeg', 'gif'])
def allowed_file(filename):
    return '.' in filename and filename.rsplit('.', 1)[1].lower() in ALLOWED_EXTENSIONS

@app.route('/')
def upload_form():
    return render_template('upload.html')

@app.route('/', methods=['POST'])
def upload_file():
    if request.method == 'POST':
        # check if the post request has the files part
        if 'files[]' not in request.files:
            flash('No file part')
            return redirect(request.url)
        files = request.files.getlist('files[]')
        for file in files:
            if file and allowed_file(file.filename):
                filename = secure_filename(file.filename)
                file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename))
        flash('File(s) successfully uploaded')
        return redirect('/')

if __name__ == "__main__":
    app.run(debug = True)

Answer 1

您应该更改代码

    @app.route('/', methods=['POST', 'GET'])
def upload_file():
    if request.method == 'POST':
        # check if the post request has the files part
        if 'files[]' not in request.files:
            flash('No file part')
            return redirect(request.url)
        files = request.files.getlist('files[]')
        for file in files:
            if file and allowed_file(file.filename):
                filename = secure_filename(file.filename)
                file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename))
        flash('File(s) successfully uploaded')
        return redirect('/')
    elif request.method == 'GET':
        return render_template('upload.html')

Answer 2

这里是upload.html:-

<form action="/upload" method="POST" enctype="multipart/form-data">
    {{ file_form.hidden_tag() }}
    {{ file_form.file }}
    {{ file_form.submit }}
  </form>

WTForms :-

from flask_wtf import FlaskForm
from wtforms import SubmitField, FileField

class FileForm(FlaskForm):
   file = FileField('File')
   submit = SubmitField('submit')

数据库模型：-

class Image(db.Model):
sno = db.Column(db.Integer, primary_key=True,)
fileName = db.Column(db.String(50), nullable=False)

app.py :-

@app.route("/upload", methods = ['GET', 'POST'])
def upload():
if ('user' in session and session['user'] == (Admin.query.filter_by(name=session['user']).first()).name):
    file_form = FileForm()
    if file_form.validate_on_submit():
        f = file_form.file.data
        print(f.filename)
        if f.filename == "":
            flash('no file')

        if allowed_image(f.filename):
            if os.path.isfile(f'{app.config["UPLOAD_FOLDER"]}/{f.filename}'):
                flash(f'file {f.filename} already have in server')
            else:
                try: 
                    f.save(os.path.join(app.config['UPLOAD_FOLDER'],secure_filename(f.filename)))
                    if os.path.isfile(f'{app.config["UPLOAD_FOLDER"]}/{f.filename}'):
                        image = Image(fileName=str(f.filename))
                        db.session.add(image)
                        db.session.commit()
                    else:
                        os.unlink(os.path.join(app.config['UPLOAD_FOLDER'],secure_filename(f.fileName)))
                        flash('could not added file in db , so file removed')
                        redirect('/dashbord')
                    flash('Image successfully uploaded')
                    # redirect('/dashbord')
                except IOError:
                    flash('Image could not be uploaded')
            return redirect('/dashbord')
        else:
            flash('That file extension is not allowed')
        return redirect('/dashbord')
return redirect('/dashbord')

使用Flask上传图像文件时出错

2 个答案: