我有一个结构如下的对象
"Office": {
"California" : {
"Contract1": {
1: {Price: 1000, Count: 5},
2: {Price: 2000, Count: 11},
3: {Price: 3000, Count: 3},
4: {Price: 2000, Count: 1},...
},
"Contract2": {
1: {Price: 7000, Count: 6},
2: {Price: 1000, Count: 4},
3: {Price: 67000, Count: 6},
4: {Price: 500, Count: 2},...
},
"Contract3": {
1: {Price: 4000, Count: 4},
2: {Price: 4000, Count: 1},
3: {Price: 5000, Count: 12},
4: {Price: 5000, Count: 2},...
}
},
"North Carolina" : {
"Contract1": {
1: {Price: 7000, Count: 4},
2: {Price: 7000, Count: 4},
3: {Price: 7000, Count: 4},
4: {Price: 7000, Count: 4},...
},
"Contract2": {
1: {Price: 6000, Count: 4},
2: {Price: 2000, Count: 10},
3: {Price: 3000, Count: 3},
4: {Price: 2000, Count: 3},...
},
"Contract3": {
1: {Price: 4000, Count: 5},
2: {Price: 2000, Count: 4},
3: {Price: 4000, Count: 3},
4: {Price: 2000, Count: 4},...
},...
}
我想将其简化为：
"Office": {
"California" : {
"Contract1": {
1: {Price: 6000, Count: 19},
2: {Price: 2000, Count: 1},...
},
"Contract2": {
1: {Price: 75000, Count: 16},
2: {Price: 500, Count: 2},...
},
"Contract3": {
1: {Price: 13000, Count: 17},
2: {Price: 5000, Count: 2},...
}
},
"North Carolina" : {
"Contract1": {
1: {Price: 21000, Count: 12},
2: {Price: 7, Count: 4},...
},
"Contract2": {
1: {Price: 11000, Count: 17},
2: {Price: 2000, Count: 3},...
},
"Contract3": {
1: {Price: 10000, Count: 12},
2: {Price: 2000, Count: 4},...
},...
}
第一个结构中每个合同下的数字对象代表过去的几个月。在第二个结构中，我想总结前三个数字对象的属性，可以将其称为1。然后第二个3将是2。这些是四分之一。
我认为我可以通过map，reduce和filter的某种组合来做到这一点，但是这些都是数组函数，并且我有一个对象，因此我不确定该怎么做。对于非ES6解决方案，我需要这样做。
任何指导将不胜感激。
答案 0 :(得分：1)
基于计数，它将动态填充所需的输出
const data = { "Office": {
"California" : {
"Contract1": {
1: {Price: 1000, Count: 5}, 2: {Price: 2000, Count: 11},
3: {Price: 3000, Count: 3}, 4: {Price: 2000, Count: 1},
5: {Price: 1000, Count: 5}, 6: {Price: 2000, Count: 11},
7: {Price: 3000, Count: 3}, 8: {Price: 2000, Count: 1},
9: {Price: 1000, Count: 5}, 10: {Price: 2000, Count: 11},
11: {Price: 3000, Count: 3}, 12: {Price: 2000, Count: 1},
},
"Contract2": {
1: {Price: 7000, Count: 6}, 2: {Price: 1000, Count: 4},
3: {Price: 67000, Count: 6}, 4: {Price: 500, Count: 2},
5: {Price: 7000, Count: 6}, 6: {Price: 1000, Count: 4},
7: {Price: 67000, Count: 6}, 8: {Price: 500, Count: 2},
9: {Price: 7000, Count: 6}, 10: {Price: 1000, Count: 4},
11: {Price: 67000, Count: 6}, 12: {Price: 500, Count: 2},
},
"Contract3": {
1: {Price: 4000, Count: 4}, 2: {Price: 4000, Count: 1},
3: {Price: 5000, Count: 12}, 4: {Price: 5000, Count: 2},
5: {Price: 4000, Count: 4}, 6: {Price: 4000, Count: 1},
7: {Price: 5000, Count: 12}, 8: {Price: 5000, Count: 2},
9: {Price: 4000, Count: 4}, 10: {Price: 4000, Count: 1},
11: {Price: 5000, Count: 12}, 12: {Price: 5000, Count: 2},
}
},
"North Carolina" : {
"Contract1": {
1: {Price: 7000, Count: 4}, 2: {Price: 7000, Count: 4},
3: {Price: 7000, Count: 4}, 4: {Price: 7000, Count: 4},
5: {Price: 7000, Count: 4}, 6: {Price: 7000, Count: 4},
7: {Price: 7000, Count: 4}, 8: {Price: 7000, Count: 4},
9: {Price: 7000, Count: 4}, 10: {Price: 7000, Count: 4},
11: {Price: 7000, Count: 4}, 12: {Price: 7000, Count: 4},
},
"Contract2": {
1: {Price: 6000, Count: 4}, 2: {Price: 2000, Count: 10},
3: {Price: 3000, Count: 3}, 4: {Price: 2000, Count: 3},
5: {Price: 6000, Count: 4}, 6: {Price: 2000, Count: 10},
7: {Price: 3000, Count: 3}, 8: {Price: 2000, Count: 3},
9: {Price: 6000, Count: 4}, 10: {Price: 2000, Count: 10},
11: {Price: 3000, Count: 3}, 12: {Price: 2000, Count: 3},
},
"Contract3": {
1: {Price: 4000, Count: 5}, 2: {Price: 2000, Count: 4},
3: {Price: 4000, Count: 3}, 4: {Price: 2000, Count: 4},
5: {Price: 4000, Count: 5}, 6: {Price: 2000, Count: 4},
7: {Price: 4000, Count: 3}, 8: {Price: 2000, Count: 4},
9: {Price: 4000, Count: 5}, 10: {Price: 2000, Count: 4},
11: {Price: 4000, Count: 3}, 12: {Price: 2000, Count: 4},
},
},
} }
let count = 3;
for(var parent in data['Office']){
let child1 = data['Office'][parent];
for(var con in child1){
child1[con] = Object.keys(child1[con]).reduce((acc,ele,index)=>{
let key = Math.trunc(index / count);
return {...acc,...{[key+1]: (key+1 in acc) ? {Price:acc[key+1]['Price']+child1[con][ele]['Price'],Count:acc[key+1]['Count']+child1[con][ele]['Count']} : child1[con][ele]}}
},{})
}
}
console.log(data)
答案 1 :(得分：0)
您可以使用我编写的适用于对象的特殊map函数以这种方式进行操作
const { pipe, fork, map, reduce, get } = rubico
const data = { "Office": {
"California" : {
"Contract1": {
1: {Price: 1000, Count: 5}, 2: {Price: 2000, Count: 11},
3: {Price: 3000, Count: 3}, 4: {Price: 2000, Count: 1},
5: {Price: 1000, Count: 5}, 6: {Price: 2000, Count: 11},
7: {Price: 3000, Count: 3}, 8: {Price: 2000, Count: 1},
9: {Price: 1000, Count: 5}, 10: {Price: 2000, Count: 11},
11: {Price: 3000, Count: 3}, 12: {Price: 2000, Count: 1},
},
"Contract2": {
1: {Price: 7000, Count: 6}, 2: {Price: 1000, Count: 4},
3: {Price: 67000, Count: 6}, 4: {Price: 500, Count: 2},
5: {Price: 7000, Count: 6}, 6: {Price: 1000, Count: 4},
7: {Price: 67000, Count: 6}, 8: {Price: 500, Count: 2},
9: {Price: 7000, Count: 6}, 10: {Price: 1000, Count: 4},
11: {Price: 67000, Count: 6}, 12: {Price: 500, Count: 2},
},
"Contract3": {
1: {Price: 4000, Count: 4}, 2: {Price: 4000, Count: 1},
3: {Price: 5000, Count: 12}, 4: {Price: 5000, Count: 2},
5: {Price: 4000, Count: 4}, 6: {Price: 4000, Count: 1},
7: {Price: 5000, Count: 12}, 8: {Price: 5000, Count: 2},
9: {Price: 4000, Count: 4}, 10: {Price: 4000, Count: 1},
11: {Price: 5000, Count: 12}, 12: {Price: 5000, Count: 2},
}
},
"North Carolina" : {
"Contract1": {
1: {Price: 7000, Count: 4}, 2: {Price: 7000, Count: 4},
3: {Price: 7000, Count: 4}, 4: {Price: 7000, Count: 4},
5: {Price: 7000, Count: 4}, 6: {Price: 7000, Count: 4},
7: {Price: 7000, Count: 4}, 8: {Price: 7000, Count: 4},
9: {Price: 7000, Count: 4}, 10: {Price: 7000, Count: 4},
11: {Price: 7000, Count: 4}, 12: {Price: 7000, Count: 4},
},
"Contract2": {
1: {Price: 6000, Count: 4}, 2: {Price: 2000, Count: 10},
3: {Price: 3000, Count: 3}, 4: {Price: 2000, Count: 3},
5: {Price: 6000, Count: 4}, 6: {Price: 2000, Count: 10},
7: {Price: 3000, Count: 3}, 8: {Price: 2000, Count: 3},
9: {Price: 6000, Count: 4}, 10: {Price: 2000, Count: 10},
11: {Price: 3000, Count: 3}, 12: {Price: 2000, Count: 3},
},
"Contract3": {
1: {Price: 4000, Count: 5}, 2: {Price: 2000, Count: 4},
3: {Price: 4000, Count: 3}, 4: {Price: 2000, Count: 4},
5: {Price: 4000, Count: 5}, 6: {Price: 2000, Count: 4},
7: {Price: 4000, Count: 3}, 8: {Price: 2000, Count: 4},
9: {Price: 4000, Count: 5}, 10: {Price: 2000, Count: 4},
11: {Price: 4000, Count: 3}, 12: {Price: 2000, Count: 4},
},
},
} }
const addContracts = (total, contract) => ({
Price: total.Price + contract.Price,
Count: total.Count + contract.Count,
})
const monthNumbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12]
const sumMonthsToQuarters = contract => {
const quartered = {
1: { Price: 0, Count: 0 },
2: { Price: 0, Count: 0 },
3: { Price: 0, Count: 0 },
4: { Price: 0, Count: 0 },
}
for (const monthNum of monthNumbers) {
const quarterNum = Math.ceil(monthNum / 3)
quartered[quarterNum] = addContracts(quartered[quarterNum], contract[monthNum])
}
return quartered
}
const x = map(map(map(sumMonthsToQuarters)))(data)
console.log(JSON.stringify(x))<script src="https://unpkg.com/rubico/index.js" crossorigin></script>