我之前曾问过这个问题的实际过程,但我确实做到了,但是只有一个错误。
async def on_voice_state_update(self, member, before, after):
def is_connected(member):
voice_client = get(self.bot.voice_clients, guild=member.guild)
return voice_client and voice_client.is_connected()
if is_connected(member):
await asyncio.sleep(9)
if member.id == 'id of member' and after.afk and not before.afk:
prevchannel = int(before.channel.id)
channel = self.bot.get_channel(prevchannel)
voice = await channel.connect()
voice.play(discord.FFmpegPCMAudio('dir of mp3 file'))
await asyncio.sleep(5)
await voice.disconnect()
else:
pass
else:
if member.id == 'id of member' and after.afk and not before.afk:
prevchannel = int(before.channel.id)
channel = self.bot.get_channel(prevchannel)
voice = await channel.connect()
voice.play(discord.FFmpegPCMAudio('dir of mp3 file'))
await asyncio.sleep(5)
await voice.disconnect()
else:
pass
我正在尝试检查漫游器是否已连接到语音通道,以便在同一时间(例如2秒后)有多个人加入afk,它会等到执行程序的下一次迭代: await asyncio.sleep(10)
尽管我相信我朝着正确的方向前进,但我似乎无法使is_connected函数正常工作。我曾想过尝试获取机器人的用户ID,并检查它是否已连接到语音通道。会是这样的:
def is_botconnected(member):
botid = self.bot.get_user('id of bot')
channel = (all the channels)
if botid in channel.members:
await asyncio.sleep(9)
#execute program
else:
#execute program
答案 0 :(得分:0)
我设法使用bot.voice_clients
使它正常工作。
async def on_voice_state_update(self, member, before, after):
def is_connected(self):
bot_client = get(self.bot.voice_clients)
return bot_client and bot_client.is_connected()
if is_connected(self):
await asyncio.sleep(9)
#execute program
else:
#execute program
因为它是齿轮,所以使用了自己。