使用React和Typescript,我正在构建一个tabs组件,您可以在其中通过顶部溢出从左到右滚动选项卡链接:滚动集。这可以与触控板一起使用,但是我需要为鼠标用户实现一种方法,以便他们可以像在此Codepen中一样单击和滚动:https://codepen.io/thenutz/full/VwYeYEE 到目前为止,我对位于“内容”标签上方的“链接”标签的代码如下:
<div className='container'>
<div className='flex-row'
sx={{ overflow: 'scroll',
'::-webkit-scrollbar': { display: 'none' },
display: flex,
flexDirection: 'row',
flexWrap: 'no-wrap' }}>
<div className='tabLinks'
sx={{display: 'flex', flexDirection: 'row', flexWrap: 'no-wrap'}}>
{React.Children.map(children, (child, index) => ( //LOOPS THROUGH TAB LINKS HERE ))}
</div>
</div>
</div>
tabLinks div是需要同时用触控板和鼠标(单击和拖动)水平滚动的div
我这样做的第一次尝试是使用react useRef为具有ClassName'tabLinks'的div创建一个ref
const ref = React.useRef<HTMLDivElement>(null)
此引用随后传递给tabLinks div,我尝试按照codepen示例实现onMouseDown事件,但在下面遇到此错误:
Property 'offsetLeft' does not exist on type 'RefObject<HTMLDivElement>'
任何帮助将不胜感激。
编辑:
这是我到目前为止尝试过的:
const ref = React.useRef<HTMLDivElement>(null)
let startX
let scrollLeft
<div className='container'>
<div className='flex-row'
sx={{ overflow: 'scroll',
'::-webkit-scrollbar': { display: 'none' },
display: flex,
flexDirection: 'row',
flexWrap: 'no-wrap' }}>
<div
className='items'
sx={{
display: 'flex',
flexDirection: 'row',
flexWrap: 'no-wrap'
}}
ref={ref}
onMouseDown={e => {
isDown= true
const offset = ref.current?.offsetLeft || 0
startX = e.pageX - offset
scrollLeft = ref.current?.scrollLeft
}}
onMouseUp={e => {
isDown = false;
}}
onMouseLeave={e => {
isDown = false
}}
onMouseMove={e => {
if(!isDown) return;
e.preventDefault();
const x = e.pageX - (ref.current?.offsetLeft ?? 0)
const walk = (x - startX) * 3; //scroll-fast
ref.scrollLeft = scrollLeft - walk
console.log(walk)
}}
>
{React.Children.map(children, (child, index) => ( //LOOPS THROUGH TAB LINKS HERE ))}
</div>
</div>
</div>
我现在收到此错误
Uncaught TypeError: Cannot add property scrollLeft, object is not extensible
at onMouseMove (index.tsx:102)
at HTMLUnknownElement.callCallback (react-dom.development.js:149)
at Object.invokeGuardedCallbackDev (react-dom.development.js:199)
at invokeGuardedCallback (react-dom.development.js:256)
at invokeGuardedCallbackAndCatchFirstError (react-dom.development.js:270)
at executeDispatch (react-dom.development.js:561)
at executeDispatchesInOrder (react-dom.development.js:583)
at executeDispatchesAndRelease (react-dom.development.js:680)
at executeDispatchesAndReleaseTopLevel (react-dom.development.js:688)
at forEachAccumulated (react-dom.development.js:662)
答案 0 :(得分:0)
const offset = ref.current?.offsetLeft ?? 0;
与以下内容相同:
scrollLeft = ref.current?.scrollLeft ?? 0;
当当前引用为空时,这确保两个变量都具有数字值。
您将需要null合并运算符。如果没有可用的,请使用:
const offset = ref.current?.offsetLeft || 0; scrollLeft = ref.current?.scrollLeft || 0;