Question

from sys import exit
from random import randint

class Map(object):

 def death(): 
    print quips[randint (0, len(quips)-1)]
    exit(1)

 def princess_lives_here():
    print "You see a beautiful Princess with a shiny crown."
    print "She offers you some cake."

    eat_it = raw_input(">")

    if eat_it == "eat it":
        print "You explode like a pinata full of frogs."
        print "The Princess cackles and eats the frogs. Yum!"
        return 'death'

    elif eat_it == "do not eat it":
        print "She throws the cake at you and it cuts off your head."
        print "The last thing you see is her munching on your face. Yum!"
        return 'death'

    elif eat_it == "make her eat it":
        print "The Princess screams as you cram the cake in her mouth."
        print "Then she smiles and cries and thank you for saving her."
        print "She points to a tiny door and says, 'The Koi needs cake too.'"
        print "She gives you the very last bit of cake and shoves you in."
        return 'gold_koi_pond'

    else:
        print "The Princess looks at you confused and just points at the cake."
        return 'princess_lives_here'

class Engine(object):

 def __init__(self, start, quips):
    self.quips = [
        "You died. You suck at this.",
        "Your mom would be proud, if she were smarter",
        "Such a luser.",
        "I have a small puppy that's better at this."
    ]
    self.start = start

 def play(self):
    next = self.start

    while True:
        print "\n-----"
        room = getattr(self, next)
        next = room()

m = Map()
e = Engine(m, "princess_lives_here")

e.play()

跟踪我进入终端是：

    Traceback (most recent call last):
  File "ec42.py", line 162, in <module>
    e.play()
  File "ec42.py", line 156, in play
    room = getattr(self, next)
TypeError: getattr(): attribute name must be string

我一直在研究这个问题太久了，并且无法确定它。主要问题是使map类在引擎类中作为对象运行。提前感谢您的帮助。

Answer 1

也许你想要这样的东西？

class Map(object):

 def __init__(self):

    self.quips = [
        "You died. You suck at this.",
        "Your mom would be proud, if she were smarter",
        "Such a luser.",
        "I have a small puppy that's better at this."
    ]

 def death(self): 
    print self.quips[randint (0, len(self.quips)-1)]
    exit(1)

 def princess_lives_here(self):
    print "You see a beautiful Princess with a shiny crown."
    print "She offers you some cake."

    eat_it = raw_input(">")

    if eat_it == "eat it":
        print "You explode like a pinata full of frogs."
        print "The Princess cackles and eats the frogs. Yum!"
        return 'death'

    elif eat_it == "do not eat it":
        print "She throws the cake at you and it cuts off your head."
        print "The last thing you see is her munching on your face. Yum!"
        return 'death'

    elif eat_it == "make her eat it":
        print "The Princess screams as you cram the cake in her mouth."
        print "Then she smiles and cries and thank you for saving her."
        print "She points to a tiny door and says, 'The Koi needs cake too.'"
        print "She gives you the very last bit of cake and shoves you in."
        return 'gold_koi_pond'

    else:
        print "The Princess looks at you confused and just points at the cake."
        return 'princess_lives_here'

class Engine(object):

 def __init__(self, map, start):
    self.quips = [
        "You died. You suck at this.",
        "Your mom would be proud, if she were smarter",
        "Such a luser.",
        "I have a small puppy that's better at this."
    ]
    self.map = map
    self.start = start

 def play(self):
    next = self.start

    while True:
        print "\n-----"
        room = getattr(self.map, next)
    next = room()

Answer 2

def __init__(self, start, quips):

...

e = Engine(m, "princess_lives_here")

这是你的问题。第二行使用参数m和“princess_lives_here”调用 init 。第一个参数应该是“princess_lives_here”，第二个参数应该是“quips”列表。

Answer 3

要返回对象的命名属性的值，您必须提供属性名称的字符串。

room = getattr(self, 'next')

来自python文档： getattr（对象，名称[，默认]）

返回object.name 的命名属性的值必须是字符串。如果字符串是对象属性之一的名称，则结果是该属性的值。例如，getattr（x，＆＃39; foobar＆＃39;）等同于x.foobar。如果named属性不存在，则返回default（如果提供），否则引发AttributeError。

Answer 4

self.start是Map的一个实例，但getattr（）的第二个参数必须是一个字符串，即属性的名称。

此外，实例方法应该将“self”作为第一个参数。

Answer 5

错误信息实际上告诉你这里有什么问题： - ）

room = getattr(self, next)

应该更加符合

room = getattr(self, 'next')

如Python documentation

中所述

但这只是问题的一部分。如果我想你在代码示例中省略了什么，你可能还需要在地图对象中添加__call__方法。否则room = getattr(self, next)没有那么多意义:-)嗯，那可能在这里缺少的其余代码; - ）

Map类的所有方法定义都缺少“self”参数。

需要将属性转换为字符串的Python

5 个答案: