我有一个包含3列的表,如下所示:
File User Rating (1-5)
------------------------------
00001 1 3
00002 1 4
00003 2 2
00004 3 5
00005 4 3
00005 3 2
00006 2 3
Etc.
我想生成一个输出以下内容的查询(针对每个用户和评级,显示文件数量以及文件百分比):
User Rating Count Percentage
-----------------------------------
1 1 3 .18
1 2 6 .35
1 3 8 .47
2 5 12 .75
2 3 4 .25
使用Postgresql,我知道如何使用以下查询创建包含前3列的查询,但我无法弄清楚如何计算GROUP BY中的百分比:
SELECT
User,
Rating,
Count(*)
FROM
Results
GROUP BY
User, Rating
ORDER BY
User, Rating
我希望百分比计算适用于每个用户/评级组。
答案 0 :(得分:28)
WITH t1 AS
(SELECT User, Rating, Count(*) AS n
FROM your_table
GROUP BY User, Rating)
SELECT User, Rating, n,
(0.0+n)/(COUNT(*) OVER (PARTITION BY User)) -- no integer divide!
FROM t1;
或者
SELECT User, Rating, Count(*) OVER w_user_rating AS n,
(0.0+Count(*) OVER w_user_rating)/(Count(*) OVER (PARTITION BY User)) AS pct
FROM your_table
WINDOW w_user_rating AS (PARTITION BY User, Rating);
我会看到其中一个或另一个是否为您的RDBMS提供了更好的查询计划。
答案 1 :(得分:8)
或者,您可以采用老派的方式 - 可以说更容易理解:
select usr.User as User ,
usr.Rating as Rating ,
usr.N as N ,
(100.0 * item.N) / total.N as Pct
from ( select User, Rating , count(*) as N
from Results
group by User , Rating
) usr
join ( select User , count(*) as N
from Results
group by User
) total on total.User = usr.User
order by usr.User, usr.Rating
干杯!
答案 2 :(得分:5)
执行此操作的最佳方法是使用window functions。
答案 3 :(得分:0)
WITH data AS
(SELECT User, Rating, Count(*) AS Count
FROM Results
GROUP BY User, Rating)
SELECT User, Rating, Count,
(0.0+n)/(SUM(Count) OVER (PARTITION BY User))
FROM data;
答案 4 :(得分:0)
在TSQL中这应该起作用
SELECT
User,
Rating,
Count(*), SUM(COUNT(*)) OVER (PARTITION BY User, Rating ORDER BY User, Rating) AS Total,
Count(*)/(SUM(COUNT(*)) OVER (PARTITION BY User, Rating ORDER BY User, Rating)) AS Percentage
FROM
Results
GROUP BY
User, Rating
ORDER BY
User, Rating