我有一个看起来像这样的json文件
{
"file": "name",
"main": [{
"question_no": "Q.1",
"question": "what is ?",
"answer": [{
"user": "John",
"comment": "It is defined as",
"value": {
"numbers": 2,
"submitted_value": [{
"time": "4:06",
"my_value": {
"value1": 5,
"value2": 10
}
},
{
"time": "13:47",
"my_value": {
"value1": 24,
"value2": 30
}
}
]
}
},
{
"user": "Sam",
"comment": "as John said above it simply means",
"value": {
"numbers": 2,
"submitted_value": [{
"time": "6:08",
"my_value": {
"value1": 9,
"value2": 10
}
},
{
"time": "15:24",
"my_value": {
"value1": 54,
"value2": 19
}
}
]
},
"closed": "no"
}
]
}]
}
我data = pd.json_normalize(file["main"], record_path='answer', meta='question_no')
时
我得到的结果是
user comment question_no value
0 John It is defined as Q.1 [{'my_value': 5, 'value_2': 10}, {'my_value': 24, 'value_2': 30}]
1 Sam as John said above it simply means Q.1 [{'my_value': 9, 'value_2': 10}, {'my_value': 54, 'value_2': 19}]
我需要访问列表value
和字典submitted_value
中的值,以将my_value and value_2
的总和作为新列。实际文件有点大,所以请也考虑处理总和所需的时间。
所需结果:
value1_sum value2_sum question_no user comment
29 40 Q.1 john It is defined as
63 29 Q.1 Sam as John said above it simply means
列的位置不是问题。
答案 0 :(得分:2)
您也可以这样做:
with open('1.json', 'r+') as f:
data = json.load(f)
df = pd.json_normalize(data['main'],
record_path=['answer', 'value', 'submitted_value'],
meta=[['question_no'], ['answer', 'user'], ['answer', 'comment']])
df = df.groupby(by=['answer.user', 'question_no', 'answer.comment'], as_index=False).sum()
print(df)
answer.user question_no answer.comment my_value.value1 my_value.value2
0 John Q.1 It is defined as 29 40
1 Sam Q.1 as John said above it simply means 63 29