Question

执行后得到以下响应 res_res = response.json（）我在下面提到了带有2个对象的示例输出，而实际输出中有更多对象

    {'restaurants': [{'restaurant':'R': {'has_menu_status': {'delivery': -1,
                                                       'takeaway': -1}},
                             'all_reviews_count': 8,
                             'average_cost_for_two': 350,
                             'book_again_url': '',
                             'book_form_web_view_url': '',
                             'cuisines': 'Momos, Chinese, Fast Food',
                             'name': 'Mumbai Masala'
                             'user_rating': {'aggregate_rating': '3.2',
                                             'rating_color': 'CDD614',
                                             'rating_obj': {'bg_color': {'tint': '500',
                                                                         'type': 'lime'},
                                                            'title': {'text': '3.2'}},
                                             'rating_text': 'Average',
                                             'votes': '9'}}},
                             {'restaurant':'R': {'has_menu_status': {'delivery': -1,
                                                       'takeaway': -1}},
                             'all_reviews_count': 4,
                             'average_cost_for_two': 300,
                             'book_again_url': '',
                             'book_form_web_view_url': '',
                             'cuisines': 'Fast Food',
                             'name' : 'Jumbo King',
                             'user_rating': {'aggregate_rating': '3.4',
                                             'rating_color': 'CDD614',
                                             'rating_obj': {'bg_color': {'tint': '500',
                                                                         'type': 'lime'},
                                                            'title': {'text': '3.4'}},
                                             'rating_text': 'Average',
                                             'votes': '7'}}}],
                            'results_found': 48,
                            'results_shown': 20,
                            'results_start': 0}

我想从每个对象中提取仅average_cost_for_two和名称并将其存储在单独的列表中。任何人都可以帮助我如何迭代我得到的json响应并获得所需的输出。提前谢谢！！！

Answer 1

要将结果存储在单独的列表（我假设是字典列表）中，请执行以下操作：

import json
test = json.loads(test_json) # It is your json from response

separate_list = [{'name': rest['restaurant']['name'], 'average_cost_for_two': rest['restaurant']['average_cost_for_two']}
                 for rest in test['restaurants']]

然后列表将如下所示：

[{'name': 'Mumbai Masala', 'average_cost_for_two': 350}, {'name': 'Jumbo King', 'average_cost_for_two': 300}]

您可以迭代和访问这样的元素：

for element in separate_list:
    print(element['name'])
    print(element['average_cost_for_two'])

使用python遍历json对象以获得每个对象的特定值

1 个答案: