具有id的div内的多个标签的选择器

Question

在jQuery中，如何为#con中的标签h1，h2，h3和p构建选择器？

与$('#con h1, #con h2, #con h3, #con p')类似，但不重复#con

Answer 1

您可以执行以下任何操作：

$("#con h1, #con h2, #con h3, #con p")   // your original

$("h1, h2, h3, p", $("#con"))            // pass jQuery object in as context

$("h1, h2, h3, p", "#con")               // pass selector in as context

$("#con").find("h1, h2, h3, p")          // do what jQuery ultimately does 
                                         // in the end when passing context
                                         // as jQuery or as string selector

<强> I've created a nice little jsFiddle that demos all of this.

Answer 2

$('h1, h2, h3, ...', $('#con'))会奏效。这将上下文设置为#con并在上下文（#con）内搜索h1，h2等。