Question

我如何编写一个循环，将console.log的所有数字都击中，直到它到达8的“乐透”位置；当循环运行时，它也会同时console.logs 8，但在此处停止？这是代码：

var randomNumber = Math.floor(Math.random() * 10);

function lottery() {
if (randomNumber === 8) {
    return randomNumber + ": Congratulations! You won!";
} else {
    return randomNumber + ": Sorry! No prize this time.";
}
};

我尝试了几次以建立一个for循环，但是它似乎并没有按照我的意愿运行。

Answer 1

也许这可以帮助您吗？

function lottery(winningNumber) {
  var won = false;
  while (!won) {
    var randomNumber = Math.floor(Math.random() * 10);
    if (randomNumber == winningNumber) {
      console.log(randomNumber + ": Congratulations! You won!");
      won = true;
    } else {
      console.log(randomNumber + ": Sorry! No prize this time.");
    }
  }
}
lottery(8);

Answer 2

您可以使用新号码再次调用函数。下面以递归方式调用彩票，为randomNumber分配一个新数字并对其进行测试。

function lottery() {
var randomNumber = Math.floor(Math.random() * 10);
if (randomNumber === 8) {
    console.log(randomNumber + ": Congratulations! You won!");
    return randomNumber + ": Congratulations! You won!";
} else {
    console.log(randomNumber + ": Sorry! No prize this time.");
    randomNumber = Math.floor(Math.random() * 10);
    lottery()
    return

}
}

Answer 3

您的意思是您只想连续生成一个新的随机数，直到它等于8？

let lottoFinished = false;

function lottery() {
    let randomNumber = Math.floor(Math.random() * 10);
    if (randomNumber === 8) {
        lottoFinished = true;
        return randomNumber + ": Congratulations! You won!";
    } else {
        return randomNumber + ": Sorry! No prize this time.";
    }
}

while (!lottoFinished) {
    console.log(lottery());
}

我尝试了此代码，它可以工作。

有什么办法可以循环吗？

3 个答案: