Question

我有一份召回报告，根据他们的召回计划（根据他们的情况确定何时应该返回的计划）为每个需要在特定日期返回办公室的患者出示信件。我有另一张表，存储每位患者（过去和现在）的所有预约。 recall_plans表中的约会是自动生成的，而约会表中的约会是手动创建的。如果一个人打电话进行预约，则不会检查召回计划报告，因此两个表中都会出现相同的约会，导致发出重复的提醒信。

我需要做两件事： （我知道我的方法不一定能解决业务问题，但这就是我的任务）

我需要制作一个显示该列表的列表每位患者的下一次预约但只有在未来。
我需要在第一列中添加一列报告显示每个患者的下一个预约所以有人可以手动识别重复的字母会针对特定患者并相应地进行干预。

召回报告查询：

SELECT description as [Plan Name], 
per.first_name + ' ' + per.last_name as [Patient],
substring (plan_start_date, 5,2) + '-' +
substring (plan_start_date, 7,2) + '-' + 
substring (plan_start_date, 1,4) as [Plan Start Date],
substring (nr.expected_return_date, 5,2) + '-' +
substring (nr.expected_return_date, 7,2) + '-' + 
substring (nr.expected_return_date, 1,4) as [Expected Return Date] 
FROM recall_plan_mstr rp, 
patient_recall_plans nr, 
patient pt, 
person per
WHERE rp.practice_id = nr.practice_id 
and rp.recall_plan_id = nr.recall_plan_id 
and nr.practice_id = pt.practice_id 
and nr.person_id = pt.person_id 
and per.person_id = pt.person_id 
and (active_plan_ind = 'Y') 
and rp.practice_id = '0025'

召回报告结果：

PLAN NAME          PATIENT          START      RETURN
------------------ ---------------- ---------- ----------
OFFICE VISIT W/ DR Charles Span     04-18-2011 12-15-2011
LIPID PANEL        Ronald Chap      04-11-2011 06-28-2011
OFFICE VISIT W/ DR Ronald Chap      04-11-2011 04-21-2011
OFFICE VISIT W/ DR Will Thor        03-31-2011 02-01-2012
PACEMAKER CHECK    Sylvia Berkly    05-03-2011 08-03-2011
OFFICE VISIT W/ DR Tim Cayle        04-13-2011 09-26-2011
OFFICE VISIT W/ DR Caferana Mercade 04-11-2011 10-08-2011
OFFICE VISIT W/ DR Susanna Calter   05-10-2011 05-07-2012
ICD CHECK          Jim Southern     04-14-2011 07-13-2011
STRESS ECHO        Don Cobey        04-28-2011 06-07-2010

约会查询：

select person_id, appt_date
from appointments 
where person_id is not null 
group by person_id, appt_date
order by person_id, appt_date desc

约会结果：

person_id                            appt_date
------------------------------------ ---------
073C8F83-CE15-4192-8E12-00006CB5A433 20091228
073C8F83-CE15-4192-8E12-00006CB5A433 20090510
073C8F83-CE15-4192-8E12-00006CB5A433 20090301
073C8F83-CE15-4192-8E12-00006CB5A433 20081006
378A281C-FAE7-43DF-BC03-00006E386680 20110509
378A281C-FAE7-43DF-BC03-00006E386680 20110217
378A281C-FAE7-43DF-BC03-00006E386680 20110124
378A281C-FAE7-43DF-BC03-00006E386680 20110111
378A281C-FAE7-43DF-BC03-00006E386680 20101207
816D4D31-3C99-4762-878D-000097883B73 20110316
816D4D31-3C99-4762-878D-000097883B73 20101216

问题：

如何从中生成列表结果的约会表每排一名患者，只有一名患者最近的约会未来？我需要写一个光标吗？那个？
我如何将此列表混合到我的召回报告所以它有一个专栏返回栏的权利显示患者的下一个预约日期（仅限未来）？都表格有一个人号GUID。

我希望我已经充分解释并提供了足够的信息。如果需要任何其他信息，请不要犹豫。

Answer 1

您的第一个问题的答案如下：

SELECT person_id, min(appt_date) as appt_date
FROM appointments 
WHERE person_id is not null
   AND now() < appt_date -- This line is database specific
GROUP BY person_id
ORDER BY person_id

你的第二个问题的答案是你需要一个左连接。如果在任何地方使用连接语法，则左连接会更容易。这是查询。

SELECT description as [Plan Name]
  , per.first_name + ' ' + per.last_name as [Patient]
  , substring (plan_start_date, 5,2) + '-' +
    substring (plan_start_date, 7,2) + '-' + 
    substring (plan_start_date, 1,4) as [Plan Start Date]
  , substring (nr.expected_return_date, 5,2) + '-' +
    substring (nr.expected_return_date, 7,2) + '-' + 
    substring (nr.expected_return_date, 1,4) as [Expected Return Date]
  , CASE
      WHEN next_appt.appt_date IS NULL
      THEN ''
      ELSE substring (next_appt.appt_date, 5,2) + '-' +
        substring (next_appt.appt_date, 7,2) + '-' + 
        substring (next_appt.appt_date, 1,4)
    END as [Next Appointment Date]
FROM recall_plan_mstr rp
  JOIN patient_recall_plans nr
    ON rp.recall_plan_id = nr.recall_plan_id
  JOIN patient pt
    ON nr.practice_id = pt.practice_id
      AND nr.person_id = pt.person_id 
  JOIN person per
    ON and per.person_id = pt.person_id
  LEFT JOIN (
        SELECT person_id, min(appt_date) as appt_date
        FROM appointments 
        WHERE person_id is not null
          AND now() < appt_date -- This line is database specific
        GROUP BY person_id
        ORDER BY person_id
      ) next_appt
    ON next_appt.person_id = pt.person_id
WHERE (active_plan_ind = 'Y') 
  AND rp.practice_id = '0025'

您会注意到我将查询格式化为易读性。请参阅http://bentilly.blogspot.com/2011/02/sql-formatting-style.html，了解我选择以我的方式格式化SQL的原因。

添加下一个约会日期

1 个答案: