在ACCESS 2007中运行以下SQL时
选择位置, COUNT(ApartmentBuildings)AS TotalBuildingsManaged From Apartments COUNT(ApartmentBuildings)> 3 按地点分组按顺序排列 COUNT(ApartmentBuildings)DESC;
我收到以下错误:
在where子句中不能有聚合函数。如何构建此查询以获取所有具有大于3的ApartmentBuildings数量的位置?
答案 0 :(得分:5)
使用having
代替where
:
Select Location, COUNT(ApartmentBuildings) AS TotalIBuildingsManaged
From Apartments
Group By Location
Having COUNT(ApartmentBuildings) > 3
Order By COUNT(ApartmentBuildings) DESC;
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答案 1 :(得分:3)
您需要使用HAVING子句
Select Location, COUNT(ApartmentBuildings) AS TotalIBuildingsManaged
From Apartments
Group By Location
HAVING COUNT(ApartmentBuildings) > 3