我会选择在我的DAO中使用@PersistenceContext来注入一个共享事务实体管理器,但由于我在两个指向2个不同持久性单元的entityManagerFactories上使用GenericDaoJpaImpl模式,所以我无法使用它。
所以现在我的应用程序中有这个配置:
entityManagerFactoryies:
<bean id="entityManagerFactoryIban0" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="persistenceXmlLocation" value="classpath:META-INF/contratto-persistence-iban0.xml" />
</bean>
<bean id="entityManagerFactoryCont0" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="persistenceXmlLocation" value="classpath:META-INF/contratto-persistence-cont0.xml" />
</bean>
<bean abstract="true" id="abstractDaoJpaImplIban0" lazy-init="false">
<property name="entityManagerFactory" ref="entityManagerFactoryIban0" />
</bean>
<bean abstract="true" id="abstractDaoJpaImplCont0" lazy-init="false">
<property name="entityManagerFactory" ref="entityManagerFactoryCont0" />
</bean>
然后我的每个DAO都是GenericDaoImpl的一个实例:
@Repository
public class GenericDaoJpaImpl<T, ID extends Serializable> implements GenericDao<T, ID> {
private Class<T> entityClass;
private EntityManagerFactory entityManagerFactory;
public void setEntityManagerFactory(EntityManagerFactory entityManagerFactory) {
this.entityManagerFactory = entityManagerFactory;
}
public GenericDaoJpaImpl() {
super();
}
public GenericDaoJpaImpl(Class<T> entityClass) {
super();
this.entityClass = entityClass;
}
/**
* @see it.alten.intesasanpaolo.contratto.dao.common.GenericDao#getItemByID(java.io.Serializable)
*/
@Override
public T getItemByID(ID id) {
EntityManager em = entityManagerFactory.createEntityManager();
return em.find(entityClass, id);
}
我以这种方式通过spring构建我的dao:
<bean id="eventMessageDao" parent="abstractDaoJpaImplCont0" class="it.alten.intesasanpaolo.contratto.dao.common.GenericDaoJpaImpl">
<constructor-arg>
<value>it.alten.intesasanpaolo.contratto.domain.event.OnlineEventMessage</value>
</constructor-arg>
</bean>
现在我想修改Spring文档中描述的GenericDaoJpaImpl不要与entityManagerFactory关联,我必须每次从entityManager创建但直接创建entityManager。
我想在上下文中定义它,我可以将它注入正确的抽象dao,从每个dao扩展。
<bean abstract="true" id="abstractDaoJpaImplIban0" lazy-init="false">
<property name="entityManagerFactory" ref="entityManagerFactoryIban0" />
</bean>
我怎样才能做到这一点?
亲切的问候 马西莫答案 0 :(得分:4)
您可以使用SharedEntityManagerBean
从EntityManager
构建交易EntityManagerFactory
:
<bean id="entityManagerFactoryIban0"
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
...
</bean>
<bean id="entityManagerIban0"
class="org.springframework.orm.jpa.support.SharedEntityManagerBean">
<property name="entityManagerFactory" ref="entityManagerFactoryIban0" />
</bean>
<bean abstract="true" id="abstractDaoJpaImplIban0" lazy-init="false">
<property name="entityManager" ref="entityManagerIban0" />
</bean>
答案 1 :(得分:0)
您可以使用SharedEntityManagerBean
在xml配置中提供持久性单元名称,如下所示:
<bean id="testDao" class="com.test.persistence.dao.BaseDAO">
<property name="entityManager">
<bean class="org.springframework.orm.jpa.support.SharedEntityManagerBean">
<property name="persistenceUnitName" value="persistence-test-unit" />
</bean>
</property>
</bean>
当然,您可以将SharedEntityManagerBean
作为单独的bean
在这里,我正在使用entityManager
BaseDAO
注入@PersistenceContext(unitName="...")