Question

     #EXTM3U
#EXT-X-DISCONTINUITY-SEQUENCE:0
#EXT-X-MEDIA-SEQUENCE:0
#EXT-X-ALLOW-CACHE:NO
#EXT-X-VERSION:2
#EXT-X-TARGETDURATION:8
#EXTINF:8,
fragment1.ts
#EXTINF:8,
fragment2.ts
#EXTINF:8,
fragment3.ts
#EXTINF:8,
fragment4.ts
#EXTINF:8,
fragment5.ts
#EXTINF:8,
fragment6.ts
#EXTINF:4,
fragment7.ts
#EXT-X-DICONTINUITY
#EXTINF:8,
fragment0.ts

如何将所有写入二维数组的单词传递给结构？

我希望我的结构具有一个#include <stdio.h> #include <stdlib.h> #include <string.h> typedef struct words { char *mas; }words; int main(void) { FILE *fp=fopen("test.txt", "r"); char str[100]; char arr[100][100]; int k=0; words_in->mas=malloc(sizeof(char)*sizeof(arr)); char *istr; printf("\nFile text\n\n"); for (int i = 0; i < 3; i++) { istr = fgets(str, 100, fp); printf("%s", istr); for (char* istr = strtok(str, " .\t\n"); istr; istr = strtok(NULL, " .\t\n")) { strcpy(arr[k++], istr); } }指针数组，而不只是一个指针。或指针的链接列表。或char个数组。

是否有可能以某种方式为结构和数组动态分配内存？

Answer 1

如果您想防止两个循环，并且准备牺牲一些内存，则可以采用这种方法

#include <stdio.h>
#include <stdlib.h>
#include <sys/types.h>
#include <sys/stat.h>
#include <unistd.h>
#include <string.h>

typedef struct words {
  char **mas;
}words;

int main()
{
    FILE *fp=fopen("test.txt", "r");

    struct stat statbuf;
    fstat(fileno(fp), &statbuf);

    long f_size = statbuf.st_size;

    words words_in;
    words_in.mas = (char**) malloc(sizeof(char*) * f_size); // In worst case each byte is one word.

    char fbuf[f_size+1];    // In worst case all bytes form one word ;

    long word_count = 0;
    while(fscanf(fp,"%s", fbuf) == 1) {
        words_in.mas[word_count] = strdup(fbuf);
        word_count++;
    }

    for (long i = 0; i < word_count; i++) {
        printf("%s\n",words_in.mas[i]);
    }
    return 0;
}

输入1

Apple
Bat
Cat

输出1

Apple
Bat
Cat

输入2

AppleBatCat

输出2

AppleBatCat

输入3

Apple Bat Cat

输出3

Apple
Bat
Cat

将数据从二维数组传递到结构

1 个答案: