Question

好吧，我想要的是：

[1] [2] [3] [4]

最后我得到：

[[1]，[2]，[3]，[4]]

我做了[i]看看是否可行，但是我真的不知道，请帮忙，我已经发送了完整的代码你们看看发生了什么，并帮助我确切地将它放在哪里，因为我是一个完整的新手在python上，我的朋友帮助我编写了代码，但他也不知道

numeroIncorreto = True  
continuaProcesso = True

lst_A = []
lst_B = []

    while continuaProcesso:
        while numeroIncorreto:
            try:
                n1 = int(input('Digite o primeiro número: '))
                n2 = int(input('Digite o segundo número: '))
                numeroIncorreto = False  
            except:
                print('Favor digitar um número correto')
        numeros = '' 
        if n2 >= 10 and n2 <= 50 and n1 >= 10 and n1 <= 50: 
            if n1>n2:
                for i in range(n2, n1+1): 
                    if i == n1:   
                        numeros += str(i) 
                    else:    
                        numeros += str(i) + ' '

                    if i%2 == 0: 
                        lst_A.append([i]) 

                    if str(i)[1] == '3' or str(i)[1] == '4': #
                        lst_B.append([i])  

            if n1<n2:
                numeroD = n2  
                for i in range(n1, n2+1):
                    if numeroD == n1: 
                        numeros += str(numeroD) 
                    else:
                        numeros += str(numeroD) + ' ' 

                    if numeroD%2 == 0: 
                        lst_A.append([numeroD])

                    if str(numeroD)[1] == '3' or str(numeroD)[1] == '4': 
                        lst_B.append([numeroD]) 

                    numeroD -= 1 

            #Visualização na tela com devido espaço         
            print('\n'+numeros+'')
            print('\nlst_A:')
            print(lst_A)
            print('\nlst_B:')
            print(lst_B)
            continuaProcesso = False
        else:
            print('Números fora do intervalo desejado.')
            print('Numero 1: ' + str(n1))
            print('Numero 2: ' + str(n2))
            numeroIncorreto = True

Answer 1

尝试2020-05-24T01:37:49.746Z - Uncaught internal server error. { MongoNetworkError: failed to connect to server [127.0.0.1:27017] on first connect [MongoNetworkError: connect ECONNREFUSED 127.0.0.1:27017] at Pool.<anonymous> (/opt/bitnami/apps/parse/htdocs/node_modules/mongodb-core/lib/topologies/server.js:564:11) at emitOne (events.js:116:13) at Pool.emit (events.js:211:7) at Connection.<anonymous> (/opt/bitnami/apps/parse/htdocs/node_modules/mongodb-core/lib/connection/pool.js:317:12) at Object.onceWrapper (events.js:317:30) at emitTwo (events.js:126:13) at Connection.emit (events.js:214:7) at Socket.<anonymous> (/opt/bitnami/apps/parse/htdocs/node_modules/mongodb-core/lib/connection/connection.js:246:50) at Object.onceWrapper (events.js:315:30) at emitOne (events.js:116:13) name: 'MongoNetworkError', errorLabels: [ 'TransientTransactionError' ], [Symbol(mongoErrorContextSymbol)]: {} } MongoNetworkError: failed to connect to server [127.0.0.1:27017] on first connect [MongoNetworkError: connect ECONNREFUSED 127.0.0.1:27017] at Pool.<anonymous> (/opt/bitnami/apps/parse/htdocs/node_modules/mongodb-core/lib/topologies/server.js:564:11) at emitOne (events.js:116:13) at Pool.emit (events.js:211:7) at Connection.<anonymous> (/opt/bitnami/apps/parse/htdocs/node_modules/mongodb-core/lib/connection/pool.js:317:12) at Object.onceWrapper (events.js:317:30) at emitTwo (events.js:126:13) at Connection.emit (events.js:214:7) at Socket.<anonymous> (/opt/bitnami/apps/parse/htdocs/node_modules/mongodb-core/lib/connection/connection.js:246:50) at Object.onceWrapper (events.js:315:30) at emitOne (events.js:116:13) 2020-05-24T01:37:38.156Z - error getting auth for sessionToken和print(*lst_A)。

Answer 2

首先将列表中的元素转换为字符串，然后将其连接为

1) File should have the word "Cat" or "Dog" 
2) Column 6 should be TRUE
3) Column 7 should be more than 7

结果

awk -F',' '$5~/Cat/ || $5~/Dog && $6=="TRUE" && $7>=7' cat.csv > catFinal.csv

如何从我的空列表中删除逗号和方括号？

2 个答案: