#Input 13 features
#Output Binary
# 297 data points
x = x.iloc[:,[0,1,2,3,4,5,6,7,8,9,10,11,12]].values
y1= y['Target'}
# Stratified K fold cross Validation
kf = StratifiedKFold(n_splits=10,random_state=None)
num_features=13
num_predictions=2
#Splitting data
for train_index, test_index in kf.split(x,y1):
x_train, x_test = x[train_index], x[test_index]
y_train, y_test = y1[train_index], y1[test_index]
# Standardization of data
sc=StandardScaler(0,1)
X_train = sc.fit_transform(x_train)
X_test = sc.transform(x_test)
print(X_train.shape) # o/p: (267,13)
Print(y_train.shape) # o/p: (267)
X_train = X_train.reshape((X_train.shape[0], X_train.shape[1], -1))
X_test = X_test.reshape((X_test.shape[0], X_test.shape[1], -1))
# Convert class vectors to binary class matrices.
y_train = np.reshape(y_train, (y_train.shape[0], num_predictions))
y_test = np.reshape(y_test, (y_test.shape[0], num_predictions))
verbose, epochs, batch_size = 1, 10, 32
n_timesteps, n_features, n_outputs = X_train.shape[1],X_train.shape[2],y_train.shape[1]
model = Sequential()
model.add(Conv1D(filters=64, kernel_size=3, activation='relu', input_shape (n_timesteps,n_features)))
model.add(Conv1D(filters=64, kernel_size=3, activation='relu'))
model.add(Dropout(0.5))
model.add(MaxPooling1D(pool_size=2))
model.add(Flatten())
model.add(Dense(100, activation='relu'))
model.add(Dense(297, activation='softmax'))
model.compile(loss='categorical_crossentropy', optimizer='adam', metrics=['accuracy'])
# fit network
model.fit(X_train, y_train, epochs=epochs, batch_size=batch_size, verbose=verbose)
# evaluate model
accuracy = model.evaluate(X_test, y_test, batch_size=batch_size, verbose=0)
print(accuracy)
我如何输入数据以输入需要3维数据的CNN。如何解决问题
ValueError:无法将大小为267的数组重塑为形状(267,2)。
答案 0 :(得分:0)
想象一下,您有100个正方形的线,并且想要使其成为矩形。您可以将其设为2x100变成矩形吗?不,但是您可以将其设置为50x2。
简而言之,您不能使矩形的值大于原始矩形。