我有很多文件夹,有很多不同日期的数据文件。现在,如果我从DatePicker中选择日期,我的代码也会提取数据并提取日期,并将日期作为名称保存到txt文件(例如YYYYMMDD.txt
,20110131.txt
),我选择了来自我的DatePicker的日期。
我在这些文件中有超过2年的数据。每次我选择提取数据的日期时,我都很难这样做。
如果我从DatePickers中选择开始日期到当前日期,则数据将从开始日期提取到当前日期,并将文件名保存为每个日期。
有什么建议吗?
这是我的代码:
private void dateTimePicker1_ValueChanged(object sender, EventArgs e)
{
DateTime dt = dateTimePicker1.Value;
txtSelectedDate.Text = dt.ToString("yyyyMMdd");
selectedDate = txtSelectedDate.Text;
}
private void button2_Click(object sender, EventArgs e)
{
string DayBgSpot = "E:\\Folder";
string DayBgSpotDestination = "E:\\Folder1";
int DT = int.Parse(txtSelectedDate.Text);
FileReader Reader = new FileReader();
FileReader Reader1 = new FileReader();
Reader.OpenDirectory(DayBgSpot);
Reader.ReadNaster();
string path = DayBgSpotDestination + "\\" + txtSelectedDate.Text + ".txt";
StreamWriter Strwriter = new StreamWriter(path);
try
{
while (Reader.iMaRecordsLeft > 0)
{
string SecName = Reader.sMaSecName;
string Symbol = Reader.sMaSecSymbol;
Symbol = prefix + Symbol;
int abc = 0;
Reader.OpenSecurityByName(Reader.sMaSecName);
if (Reader.iSeRecords > 0)
{
while (Reader.iSeRecordsLeft > 0)
{
Reader.ReadDay();
float O = Reader.dSeo;
float H = Reader.dSeh;
float L = Reader.dSel;
float C = Reader.dSec;
double V = Reader.dSeV;
double OI = Reader.dSrest;
string T = Reader.iSeTime.ToString();
string D = Reader.iSeDate.ToString();
if (int.Parse(D) == DT)
{
string a = string.Concat(SecName, ",", Symbol, ",", D, ",", T, ",", O, ",", H, ",", L, ",", C, ",", V, ",", OI);
if (SecName != "" && V != 0)
{
Strwriter.WriteLine(a);
}
}
}
}
abc++;
Reader.ReadNaster();
}
Reader.CloseDirectory();
Strwriter.Close();
Strwriter.Dispose();
}
catch
{
}
}
答案 0 :(得分:1)
这是逻辑。 可以说,您已将datetimepicker用于开始日期并生成报告直至日期。
使用按钮点击代码中的循环
DateTime stdate = Datetimepicker1.value;
while (stdate <= DateTime.Now)
{
txtSelectedDate.Text = stdate.ToString("yyyyMMdd");
selectedDate = txtSelectedDate.Text;
/* Here use your existing code as it is */
............
.........
stdate = stdate.AddDays (1); // It will get next date till present
}