Question

作为标题，我想从这里使用'decorator_from_middleware'函数：https://docs.djangoproject.com/en/2.1/_modules/django/utils/decorators/

但是我只是对如何正确使用它感到困惑。我有自定义的中间件类，并设置了所有常规中间件。我将如何整合此功能，以便在装饰器的帮助下将中间件作为每个视图的基础？

示例：假设我有一些中间件类

class SimpleMiddleware:
    def __init__(self, get_response):
        self.get_response = get_response
        # One-time configuration and initialization.

    def __call__(self, request):
        # Code to be executed for each request before
        # the view (and later middleware) are called.

        response = self.get_response(request)

        # Code to be executed for each request/response after
        # the view is called.

        return response

我将如何使用decorator_from_middleware(middleware_class):并将其应用于特定视图？

Answer 1

注意：您的中间件可能无法正常工作，因为文档声称它必须与旧式中间件方法兼容。 Check it out。

假设此代码是您的视图模块：

from django.http import HttpResponse
from django.utils.decorators import decorator_from_middleware
from myapp.middleware import SimpleMiddleware

simple_decorator = decorator_from_middleware(SimpleMiddleware)

@simple_decorator 
def some_view(request):
    return HttpResponse("Hello World")

如果要将其应用于基于类的视图，则需要装饰分派方法。您甚至可以这样写一个mixin：

class SimpleMiddlewareMixin:
    @simple_decorator 
    def dispatch(*args, **kwargs):
        return super().dispatch(*args, **kwargs)

class MyClassBasedView(SimpleMiddlewareMixin, ListView):
    ...

试图弄清楚如何使用decorator_from_middleware功能

1 个答案: