我正在阅读一个如下所示的XML文件:
<?xml version="1.0" encoding="utf-8"?>
<VehicleList>
<Vehicle>
<Item>
<Name>F-150</Name>
<Maker>Ford</Maker>
<Color>Black</Color>
<Price>30000</Price>
</Item>
<ItemSpecific>
<NameValueList>
<Name>Mileage</Name>
<Value>56000</Value>
</NameValueList>
<NameValueList>
<Name>Year</Name>
<Value>2003</Value>
</NameValueList>
</ItemSpecific>
</Vehicle>
<!-- more Vehicle nodes here -->
</Vehicles>
这是从eBay网络服务返回的样本数据,所以不要在结构上烧烤。
无论如何,我正在使用这样的代码来读取xml并将所有Vehicle放在List(of Vehicle)对象中,如下所示:
Dim vehicles = From v in doc...<Vehicle> _
Let mile = (From x In v.<ItemSpecific>.<NameValueList> Where x.<Name>.Value = "Mileage" Select x.<Value>.Value).Single _
Let year = (From z In v.<ItemSpecific>.<NameValueList> Where z.<Name>.Value = "Year" Select z.<Value>.Value).Single _
Select New Vehicle With {.Name = v.<Item>.<Name>.Value, .Maker = v.<Item>.<Maker>.Value, .Color = v.<Item>.<Color>.Value, .Mileage = mile, .Year = year}
然后将生成的List(Of Vehicle)
绑定到呈现数据的ASP.NET ListView
控件。一切顺利如果所有需要的节点都存在。例如,“里程”节点是有条件的,有时不存在。每当节点不存在时,我都会收到“Sequence contains no elements
”错误。
我已经尝试了所有我知道的事情来使事情正常运转。有没有办法测试XElement是否存在?
答案 0 :(得分:2)
这取决于节点不存在时您想要做什么。例如,如果Nothing不可接受,那么您可以从.Single切换到.SingleOrDefault。在空序列的情况下,后者将返回Nothing,并且不会抛出异常。
Dim vehicles = From v in doc...<Vehicle> _
Let mile = (From x In v.<ItemSpecific>.<NameValueList> Where x.<Name>.Value = "Mileage" Select x.<Value>.Value).SingleOrDefault _
Let year = (From z In v.<ItemSpecific>.<NameValueList> Where z.<Name>.Value = "Year" Select z.<Value>.Value).SingleOrDefault _
Select New Vehicle With {.Name = v.<Item>.<Name>.Value, .Maker = v.<Item>.<Maker>.Value, .Color = v.<Item>.<Color>.Value, .Mileage = mile, .Year = year}