Question

我的机器人可以通过提及的方式发布角色，但是我希望通过名称来命名（这样就无需对整个角色执行ping操作。这是命令的语法：!role <@user> <role name>

我正在使用discord.js@v12

const Discord = require("discord.js");

module.exports.run = async(bot, message, args) => {

  if (!message.member.roles.cache.has('706754890294099990')) return message.channel.send(`${message.author}, roles can only be assigned by admins`).then(msg => {
    setTimeout(() => {
      msg.delete()
    }, 5000);
  })

  let rMember = message.mentions.members.first()
  if (!rMember) return message.reply(`You didn't mention any user`).then(msg => {
    setTimeout(() => {
      msg.delete()
    }, 5000);
  })

  let role = message.guild.roles.cache.find(role => role.name. == args[1]) || message.mentions.roles.first()

  if (!role) return message.channel.send(`${message.author}, You haven't written any role name`).then(msg => {
    setTimeout(() => {
      msg.delete()
    }, 5000);
  })

  if (rMember.roles.cache.has(role.id)) return message.reply(`This member already has this role!`).then(msg => {
    setTimeout(() => {
      msg.delete()
    }, 5000);
  })

  if (rMember.roles.cache.has(role.id)) {

  } else {
    await (rMember.roles.add(role.id));
    message.channel.send(`${message.author} Added __${role.name}__ to ${rMember}`);
  }

}

module.exports.help = {
  name: "role"
}

Answer 1

如果您的角色名称中包含空格，则表示您的args将如下所示：['@user', 'Name', 'in', 'parts']
要获得全名，您需要将所有参数（第一个参数即用户除外）连接在一起。为此，您可以使用Array.slice()和Array.join()；这是一个例子：

let roleName = args
  .slice(1) // Take every element from index 1 to the end
  .join(' ') // Join them back with spaces

let role = message.guild.roles.cache.find(r => r.name == roleName) || message.mentions.roles.first()

空格时按名称查找角色

1 个答案: