试图解析猫鼬对象

时间:2020-05-21 06:16:52

标签: javascript node.js mongodb ejs

因此,我正在调用mongodb,但在解析数据时遇到了麻烦,因此无法将其传递给视图。我用EJS编写了前端。

这是我正在呼叫的模型:

const CourseworkSchema = new Schema({
assignment: [
    {
        type: String
    }
],
author: {
    id: {
        type: mongoose.Schema.Types.ObjectId,
        ref: 'User'
    },
    name: String
}
})

module.exports = mongoose.model('Coursework', CourseworkSchema);

这是我称呼Corsework的路线:

app.get('/dashboard', (req, res) => {
if(req.isAuthenticated()){
    if(req.user.isTeacher) {
        // render dashboard for teacher
        //let author = author._id
        let arr = Coursework.find({  })
        //console.log(arr)
        let val = JSON.stringify(arr.assignment)
        //console.log(val)
        console.log(arr.assignment)
        res.render('instructor', {arr: val, isAuth:req.isAuthenticated()})
    }else {
        // render dashboard for student
        res.render('student', {isAuth: req.isAuthenticated()})
    }
}

我需要在视图中使用分配。 每次我尝试将其字符串化时,都会显示为undefined。 如何解析它,以便可以使用属性authorassigment

任何帮助将不胜感激。

2 个答案:

答案 0 :(得分:1)

此行let arr = Coursework.find({ })返回一个文档数组。您必须遍历arr才能获得特定的任务,而简单的arr.assignment无效

例如

let arr = await Coursework.find({  })
for (const doc of arr) {
    console.log(doc.assignment);
    console.log(doc.author);
}

如下面的代码片段所示,我创建了两个CourseWork项目,然后对其进行迭代以将其记录到控制台中

const mongoose = require('mongoose');

run().catch(error => console.log(error.stack));

async function run() {
    await mongoose.connect('mongodb://localhost:27017/test', { useNewUrlParser: true });
    await mongoose.connection.dropDatabase();

    const CourseworkSchema = new mongoose.Schema({
    assignment: [
        {
            type: String
        }
    ],
    author: {
        id: {
            type: mongoose.Schema.Types.ObjectId,
            ref: 'User'
        },
        name: String
    }
    });

    const CourseWork = mongoose.model('Coursework', CourseworkSchema);

    await CourseWork.create({ assignment: "first assignment", author: { name: "first author" }});
    await CourseWork.create({ assignment: "Second assignment", author: { name: "second author" }});

    const docs = await CourseWork.find();
    console.log(docs);

    for (const doc of docs) {
        console.log(doc.assignment);
        console.log(doc.author);
    }
}

答案 1 :(得分:0)

尝试以下代码:

app.get('/dashboard', async (req, res) => {
    if(req.isAuthenticated()){
        if(req.user.isTeacher) {
            // render dashboard for teacher
            //let author = author._id
            let arr = await Coursework.find({}).lean(true).exec();
            //console.log(arr)
            /** 
              * As `.find()` returns an array & to access `assignment` field on each doc, You need to iterate over.
              * let val = JSON.stringify(arr.assignment) has to be replaced
              */
            let val = arr.map((i)=> {return JSON.stringify(i.assignment)}) // will be an array of parsed `assignment` values
            //console.log(val)
            res.render('instructor', {arr: val, isAuth:req.isAuthenticated()})
        }else {
            // render dashboard for student
            res.render('student', {isAuth: req.isAuthenticated()})
        }
    }

由于Node.Js是异步的,因此它不会等到数据库操作Coursework.find({})完成。因此,您需要等到DB find调用完成后,然后arr中将填充数据,并且仅出于打印目的,我们不需要使用.lean(),但是如果您要更改/操作其中的字段,返回的文档,则必须将猫鼬文档转换为.Js对象以供进一步使用。另外,您需要将此代码包装在try-catch块中,因为建议将async函数包装在try catch中。

注意::如果您正在使用author检查author._id-对唯一字段进行过滤,请尝试使用.findOne(),它将返回null或匹配的文档,可以帮助我们避免在数组上进行不必要的迭代。