工作簿功能

Question

我正在尝试创建一个函数，该函数需要工作簿的名称，可见属性和Activate方法作为参数。它在isVisible行上给我“对象不支持方法错误的此属性”。如何解决这个错误？谢谢

Public Function wbOpen(wbTarget As String, isVisible As Boolean, doActivate As Boolean)
    Dim wb As Workbook  
    Set wb = Workbooks.Open(wbTarget, , False)
    If isVisible = True Then wb.Visible = True
    If doActivate = True Then wb.Activate
End Function