Question

由于某些原因，我似乎无法获得PHP.net提供的基本示例。这是我的代码：

    $string = "
<?xml version='1.0' standalone='yes'?>
<movies>
 <movie>
  <title>PHP: Behind the Parser</title>
  <characters>
   <character>
    <name>Ms. Coder</name>
    <actor>Onlivia Actora</actor>
   </character>
   <character>
    <name>Mr. Coder</name>
    <actor>El Act&#211;r</actor>
   </character>
  </characters>
  <plot>
   So, this language. It's like, a programming language. Or is it a
   scripting language? All is revealed in this thrilling horror spoof
   of a documentary.
  </plot>
  <great-lines>
   <line>PHP solves all my web problems</line>
  </great-lines>
  <rating type='thumbs'>7</rating>
  <rating type='stars'>5</rating>
 </movie>
</movies>
"; 

if(!$xml=simplexml_load_string($string)) 
    echo "failed to load xml";
else {

    print_r($xml);

}

所有这些打印都是“无法加载xml”。我在这里错过了一个重要的步骤吗？

谢谢！

Answer 1

删除$string = "后结尾的行，使其看起来像$string = "<?xml.....

Answer 2

我会在PHP手册中重新格式化你的字符串声明...

$string = <<<XML
<?xml version='1.0'?> 
<document>
 <title>Forty What?</title>
 <from>Joe</from>
 <to>Jane</to>
 <body>
  I know that's the answer -- but what's the question?
 </body>
</document>
XML;

Answer 3

看起来它只是字符串变量开头的换行问题。将其更改如下。

$string = "
         ^^^^---- // error here
<?xml version='1.0' standalone='yes'?>
  <movies>
   <movie>
    ...
    ...";

$string = "<?xml version='1.0' standalone='yes'?>
  <movies>
   <movie>
    ...
    ...";

Answer 4

你需要首先将xml设置为测试，也就是你缺少一些卷曲的

$string = "<?xml version='1.0' standalone='yes'?>
<movies>
 <movie>
  <title>PHP: Behind the Parser</title>
  <characters>
   <character>
    <name>Ms. Coder</name>
    <actor>Onlivia Actora</actor>
   </character>
   <character>
    <name>Mr. Coder</name>
    <actor>El Act&#211;r</actor>
   </character>
  </characters>
  <plot>
   So, this language. It's like, a programming language. Or is it a
   scripting language? All is revealed in this thrilling horror spoof
   of a documentary.
  </plot>
  <great-lines>
   <line>PHP solves all my web problems</line>
  </great-lines>
  <rating type='thumbs'>7</rating>
  <rating type='stars'>5</rating>
 </movie>
</movies>
"; 
$xml=simplexml_load_string($string);
if(!$xml){
    echo "failed to load xml";
}else {

    print_r($xml);

}

无法使用simplexml和PHP加载xml

4 个答案: