如何获取数组中对象元素的值？

Question

我有以下数组（用于格式化的print_r）：

$result =  Array
(
    [link] => http://www.mysite.com/article/102758
    [type] => Article
    [title] => Sweetbay, PepsiCo Round the Bases
    [user] => <a href="/user/13208" title="View user profile.">pmalinowska</a> 
    [date] => 1306512291
    [node] => stdClass Object
        (
            [id] => dbcd60fee884/node/102758
            [nid] => 102758
            [uid] => 13208
            [title] => Sweetbay, PepsiCo Round the Bases
            [type] => article
            [created] => 1306412903
            [changed] => 1306512291
            [comment_count] => 0
            [name] => pmalinowska
            [url] => http://www.mysite.com/article/102758
            [path] => node/102758
            [score] => 1.2324483
        )
)

我如何获取节点元素的created属性的值？我尝试了以下内容：

$result->node->created;

$result['node']['created'];

$result->node['created']

他们都没有工作。

Answer 1

尝试

$result[ "node" ]->created

$result是一个数组，而$result[ "node" ]是一个对象

Answer 2

试试这个： $result['node']->created

Answer 3

$result['node']是一个对象，因此您必须使用object member access syntax。

所以：

echo $result['node']->created;

Answer 4

我认为$ result ['node'] - ＆gt; created;