Question

我需要确保两列中的值是唯一的（这不是“两列”索引问题）。

Table A
Column A1       Column A2

Memphis         New York     -> ok
San Francisco   Miami        -> ok
Washington      Chicago      -> ok
Miami           Las Vegas    -> Forbidden ! Miami already exists

有可能吗？

我的例子是城市，但没有集中注意力。我真正需要的是生成的十六进制ID。

Answer 1

在SQL Server中，可以借助索引视图强制实现唯一性。您还需要一个数字表（如果您还没有）与您的Table A在同一个数据库中。

这是我的测试脚本，其中包含一些注释：

CREATE TABLE MyNumbersTable (Value int);
-- You need at least 2 rows, by the number of columns
-- you are going to implement uniqueness on
INSERT INTO MyNumbersTable
SELECT 1 UNION ALL
SELECT 2;
GO
CREATE TABLE MyUniqueCities (  -- the main table
  ID int IDENTITY,
  City1 varchar(50) NOT NULL,
  City2 varchar(50) NOT NULL
);
GO
CREATE VIEW MyIndexedView
WITH SCHEMABINDING  -- this is required for creating an indexed view
AS
SELECT
  City = CASE t.Value    -- after supplying the numbers table
    WHEN 1 THEN u.City1  -- with the necessary number of rows
    WHEN 2 THEN u.City2  -- you can extend this CASE expression
  END                    -- to add more columns to the constraint
FROM dbo.MyUniqueCities u
  INNER JOIN dbo.MyNumbersTable t
    ON t.Value BETWEEN 1 AND 2  -- change here too for more columns
GO
-- the first index on an indexed view *must* be unique,
-- which suits us perfectly
CREATE UNIQUE CLUSTERED INDEX UIX_MyIndexedView ON MyIndexedView (City)
GO
-- the first two rows insert fine
INSERT INTO MyUniqueCities VALUES ('London', 'New York');
INSERT INTO MyUniqueCities VALUES ('Amsterdam', 'Prague');
-- the following insert produces an error, because of 'London'
INSERT INTO MyUniqueCities VALUES ('Melbourne', 'London');
GO
DROP VIEW MyIndexedView
DROP TABLE MyUniqueCities
DROP TABLE MyNumbersTable
GO

有用的阅读：

Answer 2

您需要添加一个约束触发器，在插入/更新后查找它。

SQL约束在两列中具有一个唯一值

2 个答案: