Question

我正在尝试编写一个脚本来清除csvs中的信息。我有一个从csv创建的pandas df，如下所示：

CUSTOMER ORDERS
  hashed_customer      firstname    lastname    email   order_id    status          timestamp
0      eater 1_uuid  1_firstname  1_lastname  1_email    12345    OPTED_IN     2020-05-14 20:45:15
1      eater 2_uuid  2_firstname  2_lastname  2_email    23456    OPTED_IN     2020-05-14 20:29:22
2      eater 3_uuid  3_firstname  3_lastname  3_email    34567    OPTED_IN     2020-05-14 19:31:55
3      eater 4_uuid  4_firstname  4_lastname  4_email    45678    OPTED_IN     2020-05-14 17:49:27
4      eater 5_uuid  5_firstname  5_lastname  5_email    56789    OPTED_IN     2020-05-14 16:22:33

我还有另一个带有hashed_customers的csv，需要从该文件中清除。因此，如果此文件中的hashed_customer位于CUSTOMER ORDERS中，则我需要从该行中删除姓氏，姓氏和电子邮件，同时保留其余部分，以使其看起来像这样：

CUSTOMER ORDERS
      hashed_customer      firstname    lastname    email   order_id    status          timestamp
    0      eater 1_uuid         NULL        NULL     NULL    12345    OPTED_IN     2020-05-14 20:45:15
    1      eater 2_uuid  2_firstname  2_lastname  2_email    23456    OPTED_IN     2020-05-14 20:29:22
    2      eater 3_uuid  3_firstname  3_lastname  3_email    34567    OPTED_IN     2020-05-14 19:31:55
    3      eater 4_uuid         NULL        NULL     NULL    45678    OPTED_IN     2020-05-14 17:49:27
    4      eater 5_uuid  5_firstname  5_lastname  5_email    56789    OPTED_IN     2020-05-14 16:22:33

我当前的脚本如下：

print('FIND ORDERS FROM OPT-OUT CUSTOMERS')
cust_opt_out_order = []
for index, row in df_in.iterrows():
    if row.hashed_eater_uuid in cust_opt_out_id:
        cust_opt_out_order.append(row.order_id)

print('REMOVE OPT-OUT FROM OPT-IN FILE')
df_cust_out = df_in[~df_in['hashed_eater_uuid'].isin(cust_opt_out_id)]

但是这将删除整个行，现在我需要保留该行，只删除该行中的名称和电子邮件元素。如何使用熊猫从一排放元素？

Answer 1

让我们这样做

df_cust_out = df_in.copy()
df_cust_out.loc[df_in['hashed_eater_uuid'].isin(cust_opt_out_id),['firstname','lastname', 'email']]=np.nan

Python熊猫从行删除

1 个答案: