Question

我正在与Socket.io和RabbitMQ建立一对一聊天

我进行一对一聊天的实现正在运行，但是我不确定实现是否正确。

roomID相当于例如42314
与其他用户匹配时，roomID是自动生成的。
逻辑很简单，用户A加入一个会议室42314，它将发射到服务器。

用户A进入会议室后，他可以发送一条消息，该消息将消息从客户端发送到服务器。

rabbit.connect("amqp://localhost", (connError, connection) => {
   connection.createChannel((channelError, channel) => {
      io.on("connection", (socket) => {
       // This is where user join the room
       // and the channel add a new queue which the room ID
         socket.on("join", (room) => {
           channel.assertQueue(room.roomID, {
                durable: false,
           });
         socket.join(room.roomID);
       });

      // This is the part where user send message to another user
      socket.on("sendMessage", (room) => {
         // Once user send a message, it will send to the queue.
         channel.sendToQueue(room.roomID, Buffer.from(room.message));

        // since the queue has the room id, whenever there is a message
       // emit it to the room.
        channel.consume(
           room.roomID,
            (msg) => {
               console.log(" Received " + msg.content.toString());

               io.in(room.roomID).emit("message", msg.content.toString());
            },
            {
             noAck: true,
            }
          );
       });
     });
   });
 });

我的问题是

我的实现正确吗？
如果有负载均衡器，此体系结构可以工作吗？

Answer 1

我认为使用RabbitMQ会增加不必要的复杂性和滞后性。您可以只用socket.io来实现，当您收到消息时，您立即将其发送给收件人

 io.on("connection", (socket) => {
  // This is where user join the room
  // and the channel add a new queue which the room ID
  socket.on("join", (room) => {
    socket.join(room.roomID);
  });

  // This is the part where user send message to another user
  socket.on("sendMessage", (room) => {
  // Once user send a message, it will send to the queue.
  // channel.sendToQueue(room.roomID, Buffer.from(room.message));

  // since the queue has the room id, whenever there is a message
  // emit it to the room.
  io.in(room.roomID).emit("message", room.message);
  });
 });

您将需要某种粘性会话，以使实现工作在负载均衡器后面。您可以阅读有关如何实现此socket io using multiple nodes

Socket.io与Rabbitmq进行一对一聊天

1 个答案: