我有一个带有1行的数据框。
col1
0学期:2020年秋季入学学生:首次新生入学日期:5/13/2020
如何将文本分为以下三列?
我的代码出错-'tuple'对象没有属性'columns'
'''
data['Term'], data['Type'], data['Date'] = data['col1'].str[:4], data['col1'].str[18:29], data['col1'].str[53:61]
data1 = data['col1'].str[6:15], data['col1'].str[31:50], data['col1'].str[62:]
data1.columns = data.columns
newdata = pd.concat([data, data1])
print(newdata)
'''
答案 0 :(得分:0)
尝试:
data['Term'], data['Type'], data['Date'] = data['col1'].str[:4], data['col1'].str[18:29], data['col1'].str[53:61]
data1=pd.DataFrame([], columns=data.columns)
data1['Term'], data1['Type'], data1['Date'] = data['col1'].str[6:15], data['col1'].str[31:50], data['col1'].str[62:]
data1.columns = data.columns
newdata = pd.concat([data, data1]).drop('col1', axis=1)
print(newdata)
通常,这一行似乎是一个问题:
data1 = data['col1'].str[6:15], data['col1'].str[31:50], data['col1'].str[62:]
等效于:
data1 = (data['col1'].str[6:15], data['col1'].str[31:50], data['col1'].str[62:])
错误消息中的这个tuple
来自哪里...