Question

我希望将类似“ ASDF”的字符串转换为像“ 123456789”这样的数字，然后可以轻松地将其转换回“ ASDF”，我该如何在python 3中执行此操作？

Answer 1

您可以使用ord将每个字符转换为其ascii值，并使用f"{1:02d}"将其格式化为相同的长度，并将它们连接在一起。然后，当您想要返回字符串时，请逆向执行此过程。

类似

def to_num(s):
    return int("1" + "".join(map(lambda a: f"{ord(a):03d}", s)))

def to_str(n):
    num = str(n)[1:]
    chunks = [num[i:i+3] for i in range(0, len(num), 3)]
    return "".join(map(lambda a: chr(int(a)), chunks))

Answer 2

那呢：

int.from_bytes("ASDF".encode('utf-8'), byteorder='big', signed=False)
1095976006

然后返回

import math
(1095976006).to_bytes(math.ceil((1095976006).bit_length() / 8), byteorder = 'big', signed=False).decode('utf-8')
'ASDF'

它使用编码/解码获取Python字符串的utf-8表示形式为字节数组，然后使用from_bytes / to_bytes将其转换为整数。所以它适用于任何字符串。令人惊讶的是，有必要计算字节数才能使用to_bytes。

Answer 3

只是想出了一种可能的方法，因为我只使用ASCII，所以应该可以：

inp = "ASDF" #Input string
bits = 8     #Amount of bits per character

num = 0      #Just some setup value, this will be our encoded number
numstr = [ord(letter) for letter in inp] #Turns the string into a list containing each of the letters ascii code
for numletter in numstr: #Loop over each letter
    num = (num<<bits)+numletter #First shift the current num stored by 8 [In binary 01010101 becomes 0101010100000000] which makes room for the next character, then adds the new character in

print("Encoded:",num) #Print the encoded number

#num = 1234, not included as we've defined it before with the encoding part
#bits = 8, same reason as above
outp = "" #Another setup value, this will be our decoded string
AND = ((2**bits)-1) #A setup constant, we'll need this later, this is a number of just 1's in binary with the length of 8.
while num>=1: #Loop over each character
     numletter = num&AND #Bitwise AND it with the constant we got earlier, this'll extract the first character in the number
     outp = chr(numletter) + outp #First convert the extracted number to it's character, then add the character to the front of the output
     num = num>>bits #Remove the extracted number and shift it back by 8

print(outp) #Print the decoded string

Answer 4

根据定义，金达有问题。根据字符串的长度，您很容易用完int。除非您在字符串表示中表示数字，否则从理论上讲是可能的，但实际上，您将需要在这些int上作为字符串数字起作用的算法。基本上，如果您只能使用ascii，请使用以26为基的表示形式：

"F"*26^0 + "D"*26^1 + "S" * 26^ 2 and so on

或者您可以只连接字符代码，这也是一个选择，尽管它似乎毫无意义-您并没有真正将字符串隐蔽到数字，只是以另一种方式打印了它的表示形式。

或者，也许您正在谈论将封闭的字符串集映射为整数-然后将您的字符串放入列表中，并将其索引用作匹配的int。

将整个ascii字符串转换为int

4 个答案: