Question

我有存储诊所，城市和诊所信息的数据库。当我在TextInput中输入城市名称时，会得到带有诊所名称的动态按钮列表。（该列表是使用GridLayout和ScrollView创建的）因此，我不知道该怎么做，因此当我单击带有诊所名称的按钮时，我会转到另一个屏幕，在该屏幕上可以看到有关该诊所的完整信息

这是我的main.py文件：

    def on_start(self):
    result_banner = self.root.ids['result_screen'].ids['result_banner']
    con = psycopg2.connect(
        host="localhost",
        database="CLINICS",
        user="postgres",
        password="1922")


    cur = con.cursor()
    city = self.root.ids['home_screen'].ids.city.text
    cur.execute("SELECT * FROM clinic WHERE city='%s'" %city)
    rows = cur.fetchall()


    self.root.ids['result_screen'].ids['result_banner'].clear_widgets()
    for row in rows:
        name_dict = {'name': row[1]}
        adress_dict = {'adress': row[2]}
        category_dict = {'category': row[4]}
        website_dict = {'site': row[5]}


        C = ClinicBanner(name=name_dict['name'])
        result_banner.add_widget(C)

    con.commit()
    cur.close()
    con.close()

这是我的ClinicBanner.py文件

class ClinicBanner(GridLayout):
rows = 1


def __init__(self, name,**kwargs):
    super(ClinicBanner, self).__init__(**kwargs)
    with self.canvas.before:
        Color(rgb=(kivy.utils.get_color_from_hex("#ffffff")))

    centre = FloatLayout()
    centre_button = Button(text=name, size_hint=(2, 1), pos_hint={"top": .2, "left": .0001},
                        background_normal='',
                        background_color=kivy.utils.get_color_from_hex("#1854D6"),
                        on_release=self.ssc
                        )

    centre.add_widget(centre_button)
    self.add_widget(centre)

猕猴桃按钮绑定

0 个答案: