Question

我正在尝试找出客户重复购买所需的平均天数。

这就是我拥有的

  Email_address, 
  Order_name, 
  Date, 
  Order_number,
  lead(date) over (partition by email_address order by Order_number) next_order_date,
  lead(Order_number) over (partition by email_address order by Order_number) next_order_number
 FROM `dbOrders` 
Group by 1,2,3,4

正在退货

 [
  {
    "Email_address": "email@test.com",
    "Order_name": "#1234",
    "Date": "2019-11-08 00:18:00 UTC",
    "Order_number": "1",
    "next_order_date": "2019-11-28 20:54:00 UTC",
    "next_order_number": "2"
  },

我现在想获得所有第一次购买和第二次购买之间的平均天数，然后是第二次和第三次购买之间的平均天数

样本数据集

|---------------------|------------------|------------------|------------------| | Email_address | Order_name | Order_number | Date | |---------------------|------------------|------------------|------------------| | test@test.com | 364 | 1 | 2019-08-11 | |---------------------|------------------|------------------|------------------| | test@test.com | 366 | 2 | 2019-08-29 | |---------------------|------------------|------------------|------------------| | j@test.com | 495 | 1 | 2019-09-04 | |---------------------|------------------|------------------|------------------| | j@test.com | 564 | 2 | 2019-10-04 | |---------------------|------------------|------------------|------------------|

我想找到两个客户的订单之间的平均时间差。 test@test.com = 18天 j@test.com = 30天

平均= 24天

Answer 1

您似乎要查询汇总查询：

select seqnum,
       avg(date_diff(date, next_date, day)) as avg_days_to_next_order
from (select o.*,
             row_number() over (partition by email_address order by date) as seqnum,
             lead(date) over (partition by email_address order by date) as next-date
      from `dbOrders`  o
     ) o
group by seqnum
order by seqnum;

计算BigQuery客户第一和第二次订单之间的平均时间（天）

1 个答案: