从意图中获取多个广播?

时间:2011-05-30 19:47:45

标签: android sms broadcastreceiver android-intent

http://mobiforge.com/developing/story/sms-messaging-android

我在上面的链接中使用了我自己的应用程序发送短信的示例代码,但是在检查我的消息的发送状态时遇到了问题。发生的事情是,我试图发送的每条消息都会弹出Toast消息。所以基本上,假设我已经发送了3条消息。当我发送第4条消息时,Toast消息将弹出4次。似乎BroadcastReceiver可能从目前使用的每个意图接收相同的广播?我无法弄清楚为什么会发生这种情况,或者如何阻止它。任何帮助或见解将不胜感激!

以下是导致此问题的具体方法:

 //---sends an SMS message to another device---
private void sendSMS(String phoneNumber, String message)
{        
    String SENT = "SMS_SENT";
    String DELIVERED = "SMS_DELIVERED";

    PendingIntent sentPI = PendingIntent.getBroadcast(this, 0,
        new Intent(SENT), 0);

    PendingIntent deliveredPI = PendingIntent.getBroadcast(this, 0,
        new Intent(DELIVERED), 0);

    //---when the SMS has been sent---
    registerReceiver(new BroadcastReceiver(){
        @Override
        public void onReceive(Context arg0, Intent arg1) {
            switch (getResultCode())
            {
                case Activity.RESULT_OK:
                    Toast.makeText(getBaseContext(), "SMS sent", 
                            Toast.LENGTH_SHORT).show();
                    break;
                case SmsManager.RESULT_ERROR_GENERIC_FAILURE:
                    Toast.makeText(getBaseContext(), "Generic failure", 
                            Toast.LENGTH_SHORT).show();
                    break;
                case SmsManager.RESULT_ERROR_NO_SERVICE:
                    Toast.makeText(getBaseContext(), "No service", 
                            Toast.LENGTH_SHORT).show();
                    break;
                case SmsManager.RESULT_ERROR_NULL_PDU:
                    Toast.makeText(getBaseContext(), "Null PDU", 
                            Toast.LENGTH_SHORT).show();
                    break;
                case SmsManager.RESULT_ERROR_RADIO_OFF:
                    Toast.makeText(getBaseContext(), "Radio off", 
                            Toast.LENGTH_SHORT).show();
                    break;
            }
        }
    }, new IntentFilter(SENT));

    //---when the SMS has been delivered---
    registerReceiver(new BroadcastReceiver(){
        @Override
        public void onReceive(Context arg0, Intent arg1) {
            switch (getResultCode())
            {
                case Activity.RESULT_OK:
                    Toast.makeText(getBaseContext(), "SMS delivered", 
                            Toast.LENGTH_SHORT).show();
                    break;
                case Activity.RESULT_CANCELED:
                    Toast.makeText(getBaseContext(), "SMS not delivered", 
                            Toast.LENGTH_SHORT).show();
                    break;                        
            }
        }
    }, new IntentFilter(DELIVERED));        

    SmsManager sms = SmsManager.getDefault();
    sms.sendTextMessage(phoneNumber, null, message, sentPI, deliveredPI);        
}

2 个答案:

答案 0 :(得分:8)

首先,每次拨打new BroadcastReceiver(){时都会有sendSMS,所以每次拨打sendSMS时,他们会堆积一次。{1}}。您可以在每个unregister(this);的底部添加BroadcastReceiver,但更好的方法是将广播接收器移出此功能。您可以onResume()中的创建+注册unregister中的onPause().

其次,请阅读此link

如果您想与pendingIntent一起发送数据,则需要帮助Android更好地区分您的待定意图... 例如

 PendingIntent deliveredPI = PendingIntent.getBroadcast(this, uniqueIdPerSMS++,
    new Intent(DELIVERED), PendingIntent.FLAG_CANCEL_CURRENT);

答案 1 :(得分:0)

这很简单就是为每个deliverPI使用一个唯一的id,因为如果不这样,那么android会认为所有相同的所有sms的deliverPi都会显示任何一个的结果(不知道是第一个还是最后一个)