Question

Q：编写一个函数，将房屋数据转换为四分之一，然后将其返回为均值数据框中的值。此数据框应为带有从2000q1到2016q3的列，并且应具有多索引格式为[“ State”，“ RegionName”]。

我已经过滤掉了未使用的列，下面是我尝试过的代码：

def quater(date):
    return str(date.year)+'q'+str(date.quarter)

def convert_housing_data_to_quarters():
    house = pd.read_csv('City_Zhvi_AllHomes.csv')
    cols = house.columns.values 
    house.drop(["RegionID", "Metro", "CountyName", "SizeRank"] ,axis=1,inplace=True)
    house.groupby(columns=[quater(pd.Timestamp(x)) for x in cols[2:]], axis=1,inplace = True)
    return house

convert_housing_data_to_quarters()

我遇到以下错误：

ValueError                                Traceback (most recent call last)
pandas/tslib.pyx in pandas.tslib.convert_str_to_tsobject (pandas/tslib.c:29408)()

pandas/src/datetime.pxd in datetime._string_to_dts (pandas/tslib.c:95676)()

ValueError: Error parsing datetime string "State" at position 0

During handling of the above exception, another exception occurred:

ValueError                                Traceback (most recent call last)
pandas/tslib.pyx in pandas.tslib.convert_str_to_tsobject (pandas/tslib.c:29833)()

pandas/tslib.pyx in pandas.tslib.parse_datetime_string (pandas/tslib.c:35434)()

/opt/conda/lib/python3.6/site-packages/dateutil/parser.py in parse(timestr, parserinfo, **kwargs)
   1181     else:
-> 1182         return DEFAULTPARSER.parse(timestr, **kwargs)
   1183 

/opt/conda/lib/python3.6/site-packages/dateutil/parser.py in parse(self, timestr, default, ignoretz, tzinfos, **kwargs)
    558         if res is None:
--> 559             raise ValueError("Unknown string format")
    560 

ValueError: Unknown string format

During handling of the above exception, another exception occurred:

ValueError                                Traceback (most recent call last)
<ipython-input-8-c6e65688298c> in <module>()
     18     return house
     19 
---> 20 convert_housing_data_to_quarters()

<ipython-input-8-c6e65688298c> in convert_housing_data_to_quarters()
     15     cols = house.columns.values
     16     house.drop(["RegionID", "Metro", "CountyName", "SizeRank"] ,axis=1,inplace=True)
---> 17     house.groupby(columns=[quater(pd.Timestamp(x)) for x in cols[2:]], axis=1,inplace = True)
     18     return house
     19 

<ipython-input-8-c6e65688298c> in <listcomp>(.0)
     15     cols = house.columns.values
     16     house.drop(["RegionID", "Metro", "CountyName", "SizeRank"] ,axis=1,inplace=True)
---> 17     house.groupby(columns=[quater(pd.Timestamp(x)) for x in cols[2:]], axis=1,inplace = True)
     18     return house
     19 

pandas/tslib.pyx in pandas.tslib.Timestamp.__new__ (pandas/tslib.c:10447)()

pandas/tslib.pyx in pandas.tslib.convert_to_tsobject (pandas/tslib.c:27555)()

pandas/tslib.pyx in pandas.tslib.convert_str_to_tsobject (pandas/tslib.c:29886)()

ValueError: could not convert string to Timestamp

这里假定日期为quater的参数是我假定的时间戳。我想要一种合并季度中的列的方法。请帮助我，谢谢您的时间。

如何在熊猫中合并列

0 个答案: