Question

出于测试目的，我有3个实例，其中2个具有key：Backup Value：Testing标记，而1个没有此标记，我想获取没有此特定标记的实例名称。我正在尝试获取所有实例名称的逻辑，然后查找具有此备份标签的实例，然后从第一个列表中删除第二个列表。我可以同时获得两个列表，但不能从第一个列表中筛选出第二个列表。

代码：

import boto3

ec2 = boto3.client('ec2')

def lambda_handler(event, context):
    response = ec2.describe_instances()
    for reservation in response["Reservations"]:
        for instance in reservation["Instances"]:

            print(instance["InstanceId"])


    tags_NV = ec2.describe_tags(
    Filters = [
        {
            'Name':'resource-type',
            'Values':['instance']
        },
        {
        'Name':'key',
        'Values':['Backup']
        }
    ]
    )

    ami_backuppolicy = {i['ResourceId'] for i in tags_NV['Tags']}
    print(ami_backuppolicy)

输出：

Function Logs:
START RequestId: c271c3b3-9c64-4d7b-829f-d34ffcb5e944 Version: $LATEST

i-05a448daa5823d6af
i-0f79ec69714932e8e
i-058bfa970112e8565

{'i-058bfa970112e8565', 'i-05a448daa5823d6af'}

END RequestId: c271c3b3-9c64-4d7b-829f-d34ffcb5e944
REPORT RequestId: c271c3b3-9c64-4d7b-829f-d34ffcb5e944  Duration: 480.40 ms Billed Duration: 500 ms Memory Size: 128 MB Max Memory Used: 73 MB  Init Duration: 276.17 ms

Answer 1

这是一个AWS Lambda函数，它将查找没有给定标签的任何实例：

import boto3

def lambda_handler(event, context):

    ec2_resource = boto3.resource('ec2')

    not_backed_up = []

    for instance in ec2_resource.instances.all():
        if not [tag for tag in instance.tags if tag['Key'] == 'Backup' and tag['Value'] == 'Testing']:
            not_backed_up.append(instance.id)

    print(not_backed_up)

Answer 2

代码：

import boto3
def lambda_handler(event, context):
    list=[]
    ec2 = boto3.client('ec2')
    ec2_resource = boto3.resource('ec2')
    response = ec2.describe_instances()
    for reservation in response["Reservations"]:
        for instance in reservation["Instances"]:

            list.append(instance["InstanceId"])

    not_backed_up = []
    list_difference = []
    for instance in ec2_resource.instances.all():
        if [tag for tag in instance.tags if tag['Key'] == 'Backup' and tag['Value'] == 'Testing']:
            not_backed_up.append(instance.id)

    print(list)
    print(not_backed_up)

    for item in list:
        if item not in not_backed_up:
         list_difference.append(item)

    print(list_difference)

输出：

功能日志： START RequestId：73fcb1b0-5421-47dc-88f6-b82f581aa461版本：$ LATEST

['i-05a448daa5823d6af'，'i-0f79ec69714932e8e'，'i-058bfa970112e8565']

['i-05a448daa5823d6af'，'i-058bfa970112e8565']

['i-0f79ec69714932e8e']

第三个输出是没有备份标记的实例

Lambda脚本，用于获取没有特定标签的实例名称

2 个答案: