我想使用mm/dd/yyyy格式验证输入上的日期格式。
我在一个站点中找到了以下代码，然后使用它但它不起作用：
function isDate(ExpiryDate) {
var objDate, // date object initialized from the ExpiryDate string
mSeconds, // ExpiryDate in milliseconds
day, // day
month, // month
year; // year
// date length should be 10 characters (no more no less)
if (ExpiryDate.length !== 10) {
return false;
}
// third and sixth character should be '/'
if (ExpiryDate.substring(2, 3) !== '/' || ExpiryDate.substring(5, 6) !== '/') {
return false;
}
// extract month, day and year from the ExpiryDate (expected format is mm/dd/yyyy)
// subtraction will cast variables to integer implicitly (needed
// for !== comparing)
month = ExpiryDate.substring(0, 2) - 1; // because months in JS start from 0
day = ExpiryDate.substring(3, 5) - 0;
year = ExpiryDate.substring(6, 10) - 0;
// test year range
if (year < 1000 || year > 3000) {
return false;
}
// convert ExpiryDate to milliseconds
mSeconds = (new Date(year, month, day)).getTime();
// initialize Date() object from calculated milliseconds
objDate = new Date();
objDate.setTime(mSeconds);
// compare input date and parts from Date() object
// if difference exists then date isn't valid
if (objDate.getFullYear() !== year ||
objDate.getMonth() !== month ||
objDate.getDate() !== day) {
return false;
}
// otherwise return true
return true;
}
function checkDate(){
// define date string to test
var ExpiryDate = document.getElementById(' ExpiryDate').value;
// check date and print message
if (isDate(ExpiryDate)) {
alert('OK');
}
else {
alert('Invalid date format!');
}
}
关于可能出错的任何建议？
答案 0 :(得分：157)
我认为Niklas对您的问题有正确的答案。除此之外，我认为以下日期验证功能更容易理解：
// Validates that the input string is a valid date formatted as "mm/dd/yyyy"
function isValidDate(dateString)
{
// First check for the pattern
if(!/^\d{1,2}\/\d{1,2}\/\d{4}$/.test(dateString))
return false;
// Parse the date parts to integers
var parts = dateString.split("/");
var day = parseInt(parts[1], 10);
var month = parseInt(parts[0], 10);
var year = parseInt(parts[2], 10);
// Check the ranges of month and year
if(year < 1000 || year > 3000 || month == 0 || month > 12)
return false;
var monthLength = [ 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 ];
// Adjust for leap years
if(year % 400 == 0 || (year % 100 != 0 && year % 4 == 0))
monthLength[1] = 29;
// Check the range of the day
return day > 0 && day <= monthLength[month - 1];
};
答案 1 :(得分：83)
我会使用Moment.js进行日期验证。
alert(moment("05/22/2012", 'MM/DD/YYYY',true).isValid()); //true
Jsfiddle：http://jsfiddle.net/q8y9nbu5/
答案 2 :(得分：35)
使用以下正则表达式进行验证：
var date_regex = /^(0[1-9]|1[0-2])\/(0[1-9]|1\d|2\d|3[01])\/(19|20)\d{2}$/ ;
if(!(date_regex.test(testDate)))
{
return false;
}
对MM / dd / yyyy来说，这对我有用。
答案 3 :(得分：25)
All credits go to elian-ebbing
对于这里的懒人我也提供了格式 yyyy-mm-dd 的功能的自定义版本。
function isValidDate(dateString)
{
// First check for the pattern
var regex_date = /^\d{4}\-\d{1,2}\-\d{1,2}$/;
if(!regex_date.test(dateString))
{
return false;
}
// Parse the date parts to integers
var parts = dateString.split("-");
var day = parseInt(parts[2], 10);
var month = parseInt(parts[1], 10);
var year = parseInt(parts[0], 10);
// Check the ranges of month and year
if(year < 1000 || year > 3000 || month == 0 || month > 12)
{
return false;
}
var monthLength = [ 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 ];
// Adjust for leap years
if(year % 400 == 0 || (year % 100 != 0 && year % 4 == 0))
{
monthLength[1] = 29;
}
// Check the range of the day
return day > 0 && day <= monthLength[month - 1];
}
答案 4 :(得分：9)
您可以使用Date.parse()
您可以阅读MDN documentation
Date.parse（）方法解析日期的字符串表示，和 返回自1970年1月1日00:00:00 UTC以来的毫秒数 如果字符串无法识别，或者在某些情况下包含，则为NaN 非法日期值（例如2015-02-31）。
并检查Date.parse的结果是否为
let isValidDate = Date.parse('01/29/1980');
if (isNaN(isValidDate)) {
// when is not valid date logic
return false;
}
// when is valid date logic
请查看建议何时在MDN中使用Date.parse
答案 5 :(得分：8)
它似乎适用于mm / dd / yyyy格式日期，例如：
http://jsfiddle.net/niklasvh/xfrLm/
我对您的代码唯一的问题是：
var ExpiryDate = document.getElementById(' ExpiryDate').value;
在元素ID之前的括号内有空格。将其更改为：
var ExpiryDate = document.getElementById('ExpiryDate').value;
如果没有关于不起作用的数据类型的任何进一步细节，则没有太多可以提供输入。
答案 6 :(得分：8)
如果给定的字符串格式正确（'MM / DD / YYYY'），该函数将返回true，否则返回false。 （我在网上发现了这个代码并对其进行了一些修改）
function isValidDate(date) {
var temp = date.split('/');
var d = new Date(temp[2] + '/' + temp[0] + '/' + temp[1]);
return (d && (d.getMonth() + 1) == temp[0] && d.getDate() == Number(temp[1]) && d.getFullYear() == Number(temp[2]));
}
console.log(isValidDate('02/28/2015'));
答案 7 :(得分：4)
以下是检查有效日期的一个代码段：
function validateDate(dateStr) {
const regExp = /^(\d\d?)\/(\d\d?)\/(\d{4})$/;
let matches = dateStr.match(regExp);
let isValid = matches;
let maxDate = [0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31];
if (matches) {
const month = parseInt(matches[1]);
const date = parseInt(matches[2]);
const year = parseInt(matches[3]);
isValid = month <= 12 && month > 0;
isValid &= date <= maxDate[month] && date > 0;
const leapYear = (year % 400 == 0)
|| (year % 4 == 0 && year % 100 != 0);
isValid &= month != 2 || leapYear || date <= 28;
}
return isValid
}
console.log(['1/1/2017', '01/1/2017', '1/01/2017', '01/01/2017', '13/12/2017', '13/13/2017', '12/35/2017'].map(validateDate));
答案 8 :(得分：3)
看到这样一个基本话题的帖子太老了，答案如此之多，没有一个是对的。 （我并不是说它们都不起作用。）
Date.parse()不应用于本地日期字符串。 MDN说：“不建议使用Date.parse，因为直到ES5为止，字符串的解析完全取决于实现。”该标准要求使用（可能是简化的）ISO 8601字符串。对其他格式的支持取决于实现方式。new Date(string)，因为它使用Date.parse（）。这是一个高效，简洁的解决方案，没有任何隐式转换。它利用Date构造函数的意愿将2018-14-29解释为2019-03-01。它确实使用了几种现代语言功能，但是如果需要，可以轻松将其删除。我还提供了一些测试。
function isValidDate(s) {
// Assumes s is "mm/dd/yyyy"
if ( ! /^\d\d\/\d\d\/\d\d\d\d$/.test(s) ) {
return false;
}
const parts = s.split('/').map((p) => parseInt(p, 10));
parts[0] -= 1;
const d = new Date(parts[2], parts[0], parts[1]);
return d.getMonth() === parts[0] && d.getDate() === parts[1] && d.getFullYear() === parts[2];
}
function testValidDate(s) {
console.log(s, isValidDate(s));
}
testValidDate('01/01/2020'); // true
testValidDate('02/29/2020'); // true
testValidDate('02/29/2000'); // true
testValidDate('02/29/1900'); // false
testValidDate('02/29/2019'); // false
testValidDate('01/32/1970'); // false
testValidDate('13/01/1970'); // false
testValidDate('14/29/2018'); // false
testValidDate('1a/2b/3ccc'); // false
testValidDate('1234567890'); // false
testValidDate('aa/bb/cccc'); // false
testValidDate(null); // false
testValidDate(''); // false
答案 9 :(得分：2)
在下面的代码中查找，该代码可以对任何提供的格式执行日期验证，以验证开始日期和结束日期。可能有一些更好的方法，但已经提出了这个。 注意提供的日期格式和日期字符串齐头并进。
<script type="text/javascript">
function validate() {
var format = 'yyyy-MM-dd';
if(isAfterCurrentDate(document.getElementById('start').value, format)) {
alert('Date is after the current date.');
} else {
alert('Date is not after the current date.');
}
if(isBeforeCurrentDate(document.getElementById('start').value, format)) {
alert('Date is before current date.');
} else {
alert('Date is not before current date.');
}
if(isCurrentDate(document.getElementById('start').value, format)) {
alert('Date is current date.');
} else {
alert('Date is not a current date.');
}
if (isBefore(document.getElementById('start').value, document.getElementById('end').value, format)) {
alert('Start/Effective Date cannot be greater than End/Expiration Date');
} else {
alert('Valid dates...');
}
if (isAfter(document.getElementById('start').value, document.getElementById('end').value, format)) {
alert('End/Expiration Date cannot be less than Start/Effective Date');
} else {
alert('Valid dates...');
}
if (isEquals(document.getElementById('start').value, document.getElementById('end').value, format)) {
alert('Dates are equals...');
} else {
alert('Dates are not equals...');
}
if (isDate(document.getElementById('start').value, format)) {
alert('Is valid date...');
} else {
alert('Is invalid date...');
}
}
/**
* This method gets the year index from the supplied format
*/
function getYearIndex(format) {
var tokens = splitDateFormat(format);
if (tokens[0] === 'YYYY'
|| tokens[0] === 'yyyy') {
return 0;
} else if (tokens[1]=== 'YYYY'
|| tokens[1] === 'yyyy') {
return 1;
} else if (tokens[2] === 'YYYY'
|| tokens[2] === 'yyyy') {
return 2;
}
// Returning the default value as -1
return -1;
}
/**
* This method returns the year string located at the supplied index
*/
function getYear(date, index) {
var tokens = splitDateFormat(date);
return tokens[index];
}
/**
* This method gets the month index from the supplied format
*/
function getMonthIndex(format) {
var tokens = splitDateFormat(format);
if (tokens[0] === 'MM'
|| tokens[0] === 'mm') {
return 0;
} else if (tokens[1] === 'MM'
|| tokens[1] === 'mm') {
return 1;
} else if (tokens[2] === 'MM'
|| tokens[2] === 'mm') {
return 2;
}
// Returning the default value as -1
return -1;
}
/**
* This method returns the month string located at the supplied index
*/
function getMonth(date, index) {
var tokens = splitDateFormat(date);
return tokens[index];
}
/**
* This method gets the date index from the supplied format
*/
function getDateIndex(format) {
var tokens = splitDateFormat(format);
if (tokens[0] === 'DD'
|| tokens[0] === 'dd') {
return 0;
} else if (tokens[1] === 'DD'
|| tokens[1] === 'dd') {
return 1;
} else if (tokens[2] === 'DD'
|| tokens[2] === 'dd') {
return 2;
}
// Returning the default value as -1
return -1;
}
/**
* This method returns the date string located at the supplied index
*/
function getDate(date, index) {
var tokens = splitDateFormat(date);
return tokens[index];
}
/**
* This method returns true if date1 is before date2 else return false
*/
function isBefore(date1, date2, format) {
// Validating if date1 date is greater than the date2 date
if (new Date(getYear(date1, getYearIndex(format)),
getMonth(date1, getMonthIndex(format)) - 1,
getDate(date1, getDateIndex(format))).getTime()
> new Date(getYear(date2, getYearIndex(format)),
getMonth(date2, getMonthIndex(format)) - 1,
getDate(date2, getDateIndex(format))).getTime()) {
return true;
}
return false;
}
/**
* This method returns true if date1 is after date2 else return false
*/
function isAfter(date1, date2, format) {
// Validating if date2 date is less than the date1 date
if (new Date(getYear(date2, getYearIndex(format)),
getMonth(date2, getMonthIndex(format)) - 1,
getDate(date2, getDateIndex(format))).getTime()
< new Date(getYear(date1, getYearIndex(format)),
getMonth(date1, getMonthIndex(format)) - 1,
getDate(date1, getDateIndex(format))).getTime()
) {
return true;
}
return false;
}
/**
* This method returns true if date1 is equals to date2 else return false
*/
function isEquals(date1, date2, format) {
// Validating if date1 date is equals to the date2 date
if (new Date(getYear(date1, getYearIndex(format)),
getMonth(date1, getMonthIndex(format)) - 1,
getDate(date1, getDateIndex(format))).getTime()
=== new Date(getYear(date2, getYearIndex(format)),
getMonth(date2, getMonthIndex(format)) - 1,
getDate(date2, getDateIndex(format))).getTime()) {
return true;
}
return false;
}
/**
* This method validates and returns true if the supplied date is
* equals to the current date.
*/
function isCurrentDate(date, format) {
// Validating if the supplied date is the current date
if (new Date(getYear(date, getYearIndex(format)),
getMonth(date, getMonthIndex(format)) - 1,
getDate(date, getDateIndex(format))).getTime()
=== new Date(new Date().getFullYear(),
new Date().getMonth(),
new Date().getDate()).getTime()) {
return true;
}
return false;
}
/**
* This method validates and returns true if the supplied date value
* is before the current date.
*/
function isBeforeCurrentDate(date, format) {
// Validating if the supplied date is before the current date
if (new Date(getYear(date, getYearIndex(format)),
getMonth(date, getMonthIndex(format)) - 1,
getDate(date, getDateIndex(format))).getTime()
< new Date(new Date().getFullYear(),
new Date().getMonth(),
new Date().getDate()).getTime()) {
return true;
}
return false;
}
/**
* This method validates and returns true if the supplied date value
* is after the current date.
*/
function isAfterCurrentDate(date, format) {
// Validating if the supplied date is before the current date
if (new Date(getYear(date, getYearIndex(format)),
getMonth(date, getMonthIndex(format)) - 1,
getDate(date, getDateIndex(format))).getTime()
> new Date(new Date().getFullYear(),
new Date().getMonth(),
new Date().getDate()).getTime()) {
return true;
}
return false;
}
/**
* This method splits the supplied date OR format based
* on non alpha numeric characters in the supplied string.
*/
function splitDateFormat(dateFormat) {
// Spliting the supplied string based on non characters
return dateFormat.split(/\W/);
}
/*
* This method validates if the supplied value is a valid date.
*/
function isDate(date, format) {
// Validating if the supplied date string is valid and not a NaN (Not a Number)
if (!isNaN(new Date(getYear(date, getYearIndex(format)),
getMonth(date, getMonthIndex(format)) - 1,
getDate(date, getDateIndex(format))))) {
return true;
}
return false;
}
</script>
以下是HTML代码段
<input type="text" name="start" id="start" size="10" value="" />
<br/>
<input type="text" name="end" id="end" size="10" value="" />
<br/>
<input type="button" value="Submit" onclick="javascript:validate();" />
答案 10 :(得分：2)
如果你想检查验证dd / MM / yyyy
，那没关系
function isValidDate(date) {
var temp = date.split('/');
var d = new Date(temp[1] + '/' + temp[0] + '/' + temp[2]);
return (d && (d.getMonth() + 1) == temp[1] && d.getDate() == Number(temp[0]) && d.getFullYear() == Number(temp[2]));
}
alert(isValidDate('29/02/2015')); // it not exist ---> false
答案 11 :(得分：1)
function fdate_validate(vi)
{
var parts =vi.split('/');
var result;
var mydate = new Date(parts[2],parts[1]-1,parts[0]);
if (parts[2] == mydate.getYear() && parts[1]-1 == mydate.getMonth() && parts[0] == mydate.getDate() )
{result=0;}
else
{result=1;}
return(result);
}
答案 12 :(得分：1)
我从另一个发现here的帖子中删除了大部分代码。我为了我的目的修改了它。这适用于我需要的东西。这可能有助于你的情况。
$(window).load(function() {
function checkDate() {
var dateFormat = /^(0?[1-9]|[12][0-9]|3[01])[\/\-](0?[1-9]|1[012])[\/\-]\d{4}$/;
var valDate = $(this).val();
if ( valDate.match( dateFormat )) {
$(this).css("border","1px solid #cccccc","color", "#555555", "font-weight", "normal");
var seperator1 = valDate.split('/');
var seperator2 = valDate.split('-');
if ( seperator1.length > 1 ) {
var splitdate = valDate.split('/');
} else if ( seperator2.length > 1 ) {
var splitdate = valDate.split('-');
}
var dd = parseInt(splitdate[0]);
var mm = parseInt(splitdate[1]);
var yy = parseInt(splitdate[2]);
var ListofDays = [31,28,31,30,31,30,31,31,30,31,30,31];
if ( mm == 1 || mm > 2 ) {
if ( dd > ListofDays[mm - 1] ) {
$(this).val("");
$(this).css("border","solid red 1px","color", "red", "font-weight", "bold");
alert('Invalid Date! You used a date which does not exist in the known calender.');
return false;
}
}
if ( mm == 2 ) {
var lyear = false;
if ( (!(yy % 4) && yy % 100) || !(yy % 400) ){
lyear = true;
}
if ( (lyear==false) && (dd>=29) ) {
$(this).val("");
$(this).css("border","solid red 1px","color", "red", "font-weight", "bold");
alert('Invalid Date! You used Feb 29th for an invalid leap year');
return false;
}
if ( (lyear==true) && (dd>29) ) {
$(this).val("");
$(this).css("border","solid red 1px","color", "red", "font-weight", "bold");
alert('Invalid Date! You used a date greater than Feb 29th in a valid leap year');
return false;
}
}
} else {
$(this).val("");
$(this).css("border","solid red 1px","color", "red", "font-weight", "bold");
alert('Date format was invalid! Please use format mm/dd/yyyy');
return false;
}
};
$('#from_date').change( checkDate );
$('#to_date').change( checkDate );
});
答案 13 :(得分：1)
扩展（或更好地收缩）@Jay Dunnings 答案，以下双线使用 Intl API 和 ES6 解构。它通过了 Jay Dunning 给出的所有测试。
/**
* @param {string} date
* @returns {boolean} true if date is of the form mm/dd/yyyy
*/
function is_en_US_date(date) {
const [match, mm, dd, yyyy] = /^(\d\d)[/](\d\d)[/](\d{4})$/.exec(date) || [];
return match !== undefined && new Intl.DateTimeFormat('en-US', { month: '2-digit', day: '2-digit', year: 'numeric' }).format(new Date(yyyy, mm-1, dd)) === date
}
答案 14 :(得分：0)
类似于Elian Ebbing的答案，但支持“\”，“/”，“。”，“ - ”，“”分隔符
function js_validate_date_dmyyyy(js_datestr)
{
var js_days_in_year = [ 0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 ];
var js_datepattern = /^(\d{1,2})([\.\-\/\\ ])(\d{1,2})([\.\-\/\\ ])(\d{4})$/;
if (! js_datepattern.test(js_datestr)) { return false; }
var js_match = js_datestr.match(js_datepattern);
var js_day = parseInt(js_match[1]);
var js_delimiter1 = js_match[2];
var js_month = parseInt(js_match[3]);
var js_delimiter2 = js_match[4];
var js_year = parseInt(js_match[5]);
if (js_is_leap_year(js_year)) { js_days_in_year[2] = 29; }
if (js_delimiter1 !== js_delimiter2) { return false; }
if (js_month === 0 || js_month > 12) { return false; }
if (js_day === 0 || js_day > js_days_in_year[js_month]) { return false; }
return true;
}
function js_is_leap_year(js_year)
{
if(js_year % 4 === 0)
{
if(js_year % 100 === 0)
{
if(js_year % 400 === 0)
{
return true;
}
else return false;
}
else return true;
}
return false;
}
答案 15 :(得分：0)
瞬间确实是解决它的一个好方法。我看不出有增加检查日期的复杂性的原因……请看一下时刻：http://momentjs.com/
HTML：
<input class="form-control" id="date" name="date" onchange="isValidDate(this);" placeholder="DD/MM/YYYY" type="text" value="">
脚本：
function isValidDate(dateString) {
var dateToValidate = dateString.value
var isValid = moment(dateToValidate, 'MM/DD/YYYY',true).isValid()
if (isValid) {
dateString.style.backgroundColor = '#FFFFFF';
} else {
dateString.style.backgroundColor = '#fba';
}
};
答案 16 :(得分：0)
将第一个字符串日期转换为js日期格式，然后再次转换为字符串格式，然后将其与原始字符串进行比较。
function dateValidation(){
var dateString = "34/05/2019"
var dateParts = dateString.split("/");
var date= new Date(+dateParts[2], dateParts[1] - 1, +dateParts[0]);
var isValid = isValid( dateString, date );
console.log("Is valid date: " + isValid);
}
function isValidDate(dateString, date) {
var newDateString = ( date.getDate()<10 ? ('0'+date.getDate()) : date.getDate() )+ '/'+ ((date.getMonth() + 1)<10? ('0'+(date.getMonth() + 1)) : (date.getMonth() + 1) ) + '/' + date.getFullYear();
return ( dateString == newDateString);
}
答案 17 :(得分：0)
我们可以使用自定义功能或日期模式。下面的代码是根据您的要求定制的功能，请对其进行更改。
function isValidDate(str) {
var getvalue = str.split('-');
var day = getvalue[2];
var month = getvalue[1];
var year = getvalue[0];
if(year < 1901 && year > 2100){
return false;
}
if (month < 1 && month > 12) {
return false;
}
if (day < 1 && day > 31) {
return false;
}
if ((month==4 && month==6 && month==9 && month==11) && day==31) {
return false;
}
if (month == 2) { // check for february 29th
var isleap = (year % 4 == 0 && (year % 100 != 0 || year % 400 == 0));
if (day>29 || (day==29 && !isleap)) {
return false;
}
}
else{
return true;
}
}
答案 18 :(得分：0)
日期很复杂。 验证它的最佳方法是使用 Luxon 、date-fns 或 DayJS 之类的包。
使用日期-fns：
import {isMatch} from 'date-fns'
const match = isMatch(new Date('12/25/2010'), 'MM/dd/YYYY') // true
答案 19 :(得分：0)
function validatedate(inputText, DateFormat) {
// format dd/mm/yyyy or in any order of (dd or mm or yyyy) you can write dd or mm or yyyy in first or second or third position ... or can be slash"/" or dot"." or dash"-" in the dates formats
var invalid = "";
var dt = "";
var mn = "";
var yr = "";
var k;
var delm = DateFormat.includes("/") ? "/" : ( DateFormat.includes("-") ? "-" : ( DateFormat.includes(".") ? "." : "" ) ) ;
var f1 = inputText.split(delm);
var f2 = DateFormat.split(delm);
for(k=0;k<=2;k++) {
dt = dt + (f2[parseInt(k)]=="dd" ? f1[parseInt(k)] : "");
mn = mn + (f2[parseInt(k)]=="mm" ? f1[parseInt(k)] : "");
yr = yr + (f2[parseInt(k)]=="yyyy" ? f1[parseInt(k)] : "");
}
var mn_days = "0-31-" + (yr % 4 == 0 ? 29 : 28) + "-31-30-31-30-31-31-30-31-30-31";
var days = mn_days.split("-");
if (f1.length!=3 ||
mn.length>2 ||
dt.length>2 ||
yr.length!=4 ||
!(parseInt(mn)>=1 && parseInt(mn)<=12) ||
!(parseInt(yr)>=parseInt(1900) && parseInt(yr)<=parseInt(2100)) ||
!(parseInt(dt)>=1 && parseInt(dt)<=parseInt(days[parseInt(mn)]))) {
invalid = "true";
}
alert( ( invalid=="true" ? "Invalid Date" : "Valid Date") );
}
答案 20 :(得分：-1)
Javascript
function validateDate(date) {
try {
new Date(date).toISOString();
return true;
} catch (e) {
return false;
}
}
jQuery
$.fn.validateDate = function() {
try {
new Date($(this[0]).val()).toISOString();
return true;
} catch (e) {
return false;
}
}
对于有效的日期字符串返回true。
答案 21 :(得分：-1)
function validatedate(inputText, dateFormat) {
var minYear = 1950;
var maxYear = 2050;
inputText = inputText.replace("A", "a");
inputText = inputText.replace("B", "b");
inputText = inputText.replace("C", "c");
inputText = inputText.replace("D", "d");
inputText = inputText.replace("E", "e");
inputText = inputText.replace("F", "f");
inputText = inputText.replace("G", "g");
inputText = inputText.replace("H", "h");
inputText = inputText.replace("I", "i");
inputText = inputText.replace("J", "j");
inputText = inputText.replace("K", "k");
inputText = inputText.replace("L", "l");
inputText = inputText.replace("M", "m");
inputText = inputText.replace("O", "o");
inputText = inputText.replace("P", "p");
inputText = inputText.replace("Q", "q");
inputText = inputText.replace("R", "r");
inputText = inputText.replace("S", "s");
inputText = inputText.replace("T", "t");
inputText = inputText.replace("U", "u");
inputText = inputText.replace("V", "v");
inputText = inputText.replace("W", "w");
inputText = inputText.replace("X", "x");
inputText = inputText.replace("Y", "y");
inputText = inputText.replace("Z", "z");
if (dateFormat == "dd/mmm/yyyy" || dateFormat == "dd-mmm-yyyy" || dateFormat == "dd.mmm.yyyy" || dateFormat == "dd/yyyy/mmm" || dateFormat == "dd-yyyy-mmm" || dateFormat == "dd.yyyy.mmm" || dateFormat == "mmm/dd/yyyy" || dateFormat == "mmm-dd-yyyy" || dateFormat == "mmm.dd.yyyy" || dateFormat == "mmm/yyyy/dd" || dateFormat == "mmm-yyyy-dd" || dateFormat == "mmm.yyyy.dd" || dateFormat == "yyyy/mmm/dd" || dateFormat == "yyyy-mmm-dd" || dateFormat == "yyyy.mmm.dd" || dateFormat == "yyyy/dd/mmm" || dateFormat == "yyyy-dd-mmm" || dateFormat == "yyyy.dd.mmm") {
dateFormat = dateFormat.replace("mmm", "mm");
inputText = inputText.replace("jan", "01");
inputText = inputText.replace("feb", "02");
inputText = inputText.replace("mar", "03");
inputText = inputText.replace("apr", "04");
inputText = inputText.replace("may", "05");
inputText = inputText.replace("jun", "06");
inputText = inputText.replace("jul", "07");
inputText = inputText.replace("aug", "08");
inputText = inputText.replace("sep", "09");
inputText = inputText.replace("oct", "10");
inputText = inputText.replace("nov", "11");
inputText = inputText.replace("dec", "12");
}
var w;
var q;
var delm;
delm1 = "/";
for (w = 0; w < inputText.length; w++) {
q = inputText.charAt(w);
if (q == '0' || q == '1' || q == '2' || q == '3' || q == '4' || q == '5' || q == '6' || q == '7' || q == '8' || q == '9' || q == '/') {} else {
delm1 = "";
}
}
delm2 = "-";
for (w = 0; w < inputText.length; w++) {
q = inputText.charAt(w);
if (q == '0' || q == '1' || q == '2' || q == '3' || q == '4' || q == '5' || q == '6' || q == '7' || q == '8' || q == '9' || q == '-') {} else {
delm2 = "";
}
}
delm3 = ".";
for (w = 0; w < inputText.length; w++) {
q = inputText.charAt(w);
if (q == '0' || q == '1' || q == '2' || q == '3' || q == '4' || q == '5' || q == '6' || q == '7' || q == '8' || q == '9' || q == '.') {} else {
delm3 = "";
}
}
var delm;
if (delm1 == "/" && (dateFormat == "dd/mm/yyyy" || dateFormat == "mm/dd/yyyy" || dateFormat == "dd/yyyy/mm" || dateFormat == "mm/yyyy/dd" || dateFormat == "yyyy/mm/dd" || dateFormat == "yyyy/dd/mm")) {
delm = "/";
}
if (delm2 == "-" && (dateFormat == "dd-mm-yyyy" || dateFormat == "mm-dd-yyyy" || dateFormat == "dd-yyyy-mm" || dateFormat == "mm-yyyy-dd" || dateFormat == "yyyy-mm-dd" || dateFormat == "yyyy-dd-mm")) {
delm = "-";
}
if (delm3 == "." && (dateFormat == "dd.mm.yyyy" || dateFormat == "mm.dd.yyyy" || dateFormat == "dd.yyyy.mm" || dateFormat == "mm.yyyy.dd" || dateFormat == "yyyy.mm.dd" || dateFormat == "yyyy.dd.mm")) {
delm = ".";
}
var invalid;
var f = "31/12/2000";
f = inputText;
var ln = f.length;
var dt;
var mn;
var yr;
var t = f.split(delm);
var j = t.length;
if (j == 3) {
dt = t[0];
mn = t[1];
yr = t[2];
if (dateFormat == "mm.dd.yyyy" || dateFormat == "mm/dd/yyyy" || dateFormat == "mm-dd-yyyy") {
var tmp = mn;
mn = dt;
dt = tmp;
}
if (dateFormat == "dd.yyyy.mm" || dateFormat == "dd/yyyy/mm" || dateFormat == "dd-yyyy-mm") {
var tmp = mn;
mn = yr;
yr = tmp;
}
if (dateFormat == "mm.yyyy.dd" || dateFormat == "mm/yyyy/dd" || dateFormat == "mm-yyyy-dd") {
var m1 = mn;
var d1 = dt;
var y1 = yr;
mn = d1;
yr = m1;
dt = y1;
}
if (dateFormat == "yyyy.mm.dd" || dateFormat == "yyyy/mm/dd" || dateFormat == "yyyy-mm-dd") {
var m1 = mn;
var d1 = dt;
var y1 = yr;
mn = m1;
yr = d1;
dt = y1;
}
if (dateFormat == "yyyy.dd.mm" || dateFormat == "yyyy/dd/mm" || dateFormat == "yyyy-dd-mm") {
var m1 = mn;
var d1 = dt;
var y1 = yr;
mn = y1;
yr = d1;
dt = m1;
}
if (parseInt(yr) >= parseInt(minYear) && parseInt(yr) <= parseInt(maxYear)) {
// do nothing
} else {
invalid = "true";
}
if (mn.length > 2) {
invalid = "true";
}
if (dt.length > 2) {
invalid = "true";
}
if (t[0] == "") {
invalid = "true";
}
if (t[1] == "") {
invalid = "true";
}
if (t[2] == "") {
invalid = "true";
}
if (j != 3) {
invalid = "true";
}
var dc;
var daysArray = "0-31-28-31-30-31-30-31-31-30-31-30-31";
if ((yr % 4) == 0) {
daysArray = "0-31-29-31-30-31-30-31-31-30-31-30-31";
}
var days = daysArray.split("-");
if (parseInt(dt) >= 1 && parseInt(dt) <= days[parseInt(mn)]) {} else {
invalid = "true";
}
if (yr.length != 4) {
invalid = "true";
}
var i;
var m;
for (i = 0; i < ln; i++) {
m = f.charAt(i);
if (m == '0' || m == '1' || m == '2' || m == '3' || m == '4' || m == '5' || m == '6' || m == '7' || m == '8' || m == '9' || m == delm) {} else {
invalid = "true";
}
}
} else {
invalid = "true";
}
if (invalid == "true") {
alert("Invalid Date");
} else {
alert("valid Date");
}
}答案 22 :(得分：-3)
var date = new Date(date_string)
为任何无效的date_string返回文字'Invalid Date'。
注意：请参阅下面的评论。