我在使用viewmodels作为ItemsSource的动态菜单渲染图标时出现问题 我在这里概述了我使用的解决方案 MVVM Dynamic Menu UI from binding with ViewModel
基本布局如下
<Grid>
<Grid.Resources>
<HierarchicalDataTemplate DataType="{x:Type ViewModels:HeaderedItemViewModel}"
ItemsSource="{Binding Path=Children}">
<ContentPresenter RecognizesAccessKey="True"></ContentPresenter>
</HierarchicalDataTemplate>
<Style TargetType="{x:Type MenuItem}">
<Setter Property="Header" Value="{Binding Path=Header}" />
<Setter Property="InputGestureText" Value="{Binding Path=InputGestureText}" />
<Setter Property="Command" Value="{Binding Path=Command}" />
<Setter Property="Icon">
<Setter.Value>
<Image Source="{Binding Path=Icon}" Height="16px" Width="16px" />
</Setter.Value>
</Setter>
</Style>
</Grid.Resources>
<Menu Grid.Row="0" ItemsSource="{Binding Path=Shell.Navigation.Menus}" />
</Grid>
在上面的样式中,绑定'Icon'是'ImageSource'。设置如下。
BitmapImage image = null;
if (!string.IsNullOrEmpty(imagePath))
{
image = new BitmapImage(new Uri(imagePath, UriKind.Relative));
image.CacheOption = BitmapCacheOption.OnLoad;
image.CreateOptions = BitmapCreateOptions.IgnoreImageCache;
}
var menu = new HeaderedItemViewModel
{
Header = header,
InputGestureText = inputGesture,
ImagePath = imagePath,
Icon = image,
Command = command,
IsEnabled = isEnabled
};
我遇到的问题是图标 似乎一次只会渲染一个图标?这是我的意思。
打开下拉菜单......
只要渲染了另一张图像,第一张图像就会消失?换句话说,只有最后一个图像是可见的。菜单中的所有图像都会发生这种情况。有什么想法吗?
答案 0 :(得分:38)
为您的Icon值添加x:Shared = false。 要做到这一点,你应该在资源中声明Image:
<Grid>
<Grid.Resources>
<Image x:Key="imgCTX" x:Shared="false"
Source="{Binding Path=Icon}" Height="16px" Width="16px"/>
<HierarchicalDataTemplate DataType="{x:Type ViewModels:HeaderedItemViewModel}"
ItemsSource="{Binding Path=Children}">
<ContentPresenter RecognizesAccessKey="True"></ContentPresenter>
</HierarchicalDataTemplate>
<Style TargetType="{x:Type MenuItem}">
<Setter Property="Header" Value="{Binding Path=Header}" />
<Setter Property="InputGestureText" Value="{Binding Path=InputGestureText}" />
<Setter Property="Command" Value="{Binding Path=Command}" />
<Setter Property="Icon" Value="{StaticResource imgCTX}" />
</Style>
</Grid.Resources>
<Menu Grid.Row="0" ItemsSource="{Binding Path=Shell.Navigation.Menus}" />
</Grid>
答案 1 :(得分:0)
我已经搜索了各种响应,并且x:Shared =“ false”确实可以帮助您,但是您还需要正确设置所有内容以确保其有效,并且花了我一些时间才能找到正确的解决方案。这就是我如何使之发挥作用的
<ContextMenu ItemsSource="{Binding MenuElements}">
<ContextMenu.Resources>
<ControlTemplate x:Key="MenuSeparatorTemplate">
<Separator />
</ControlTemplate>
<Image
x:Key="MenuIcon"
Width="16"
Height="16"
x:Shared="False"
Source="{Binding Icon}" />
</ContextMenu.Resources>
<ContextMenu.ItemContainerStyle>
<Style TargetType="{x:Type MenuItem}">
<Setter Property="Header" Value="{Binding Name}" />
<Setter Property="ItemsSource" Value="{Binding Childs}" />
<Setter Property="Command" Value="{Binding Run}" />
<Setter Property="Icon" Value="{StaticResource MenuIcon}" />
<Style.Triggers>
<DataTrigger Binding="{Binding IsSeparator}" Value="true">
<Setter Property="Template" Value="{StaticResource MenuSeparatorTemplate}" />
</DataTrigger>
</Style.Triggers>
</Style>
</ContextMenu.ItemContainerStyle>
</ContextMenu>
通过这种方式,我可以使上下文菜单根据输入动态加载图标。