检查一个列的值是否在Pandas中另一列的正负10％范围内

Question

给出如下数据框：

        id  value1     value2
0  3918703    62.0  64.705882
1  3919144    60.0  60.000000
2  3919534    62.5  30.000000
3  3919559    55.0  55.000000
4  3920438    82.0  82.031250
5  3920463    71.0  71.428571
6  3920502    70.0  69.230769
7  3920535    80.0  40.000000
8  3920674    62.0  62.222222
9  3920856    80.0  79.987176

我要检查value2是否在value1的正负10％范围内，并返回新列result_review。

如果它不在要求的范围内，则将No表示为result_review的值。

        id  value1     value2 results_review
0  3918703    62.0  64.705882            NaN
1  3919144    60.0  60.000000            NaN
2  3919534    62.5  30.000000             no
3  3919559    55.0  55.000000            NaN
4  3920438    82.0  82.031250            NaN
5  3920463    71.0  71.428571            NaN
6  3920502    70.0  69.230769            NaN
7  3920535    80.0  40.000000             no
8  3920674    62.0  62.222222            NaN
9  3920856    80.0  79.987176            NaN

如何在熊猫中做到这一点？感谢您的提前帮助。

Answer 1

将Series.between与DataFrame.loc一起使用：

m = df['value2'].between(df['value1'].mul(0.9), df['value1'].mul(1.1))
df.loc[~m, 'results_review'] = 'no'
print (df)
        id  value1     value2 results_review
0  3918703    62.0  64.705882            NaN
1  3919144    60.0  60.000000            NaN
2  3919534    62.5  30.000000             no
3  3919559    55.0  55.000000            NaN
4  3920438    82.0  82.031250            NaN
5  3920463    71.0  71.428571            NaN
6  3920502    70.0  69.230769            NaN
7  3920535    80.0  40.000000             no
8  3920674    62.0  62.222222            NaN
9  3920856    80.0  79.987176            NaN