Question

我有两个列表（这些记录将长达数百条），但这是示例：

eax

我想从list2取出每个OUI，其中VLAN在两个列表之间匹配，然后将其添加到list1中OUI项的值。（我想这可能需要第三个命令来容纳所有内容）。

最终结果将类似于：

list1 = [
{'VENDOR': 'VENDOR1', 'VLAN': '500', 'OUI': []},
{'VENDOR': 'VENDOR2', 'VLAN': '600', 'OUI': []},
{'VENDOR': 'VENDOR3', 'VLAN': '700', 'OUI': []},
]

list2 = [
{'VLAN': '500', 'OUI': '0001FC'},
{'VLAN': '600', 'OUI': '00D024'},
{'VLAN': '500', 'OUI': '00D024'},
{'VLAN': '700', 'OUI': '00D024'},
{'VLAN': '700', 'OUI': '023456'},
]

我什至不知道从哪里开始，所以我们将不胜感激。

Answer 1

这是一种实现方法，关于

（我想这可能需要第三个命令来容纳所有内容）

那不是必须的

list1 = [
  {'VENDOR': 'VENDOR1', 'VLAN': '500', 'OUI': []},
  {'VENDOR': 'VENDOR2', 'VLAN': '600', 'OUI': []},
  {'VENDOR': 'VENDOR3', 'VLAN': '700', 'OUI': []},
]

list2 = [
  {'VLAN': '500', 'OUI': '0001FC'},
  {'VLAN': '600', 'OUI': '00D024'},
  {'VLAN': '500', 'OUI': '00D024'},
  {'VLAN': '700', 'OUI': '00D024'},
  {'VLAN': '700', 'OUI': '023456'},
]

# to hold indexes of VLAN in list1 so it will be easy to 
# append to the right "OUI" list inside list1
indexes = {}

# get the index of each VLAN
for i in range(len(list1)):
  indexes[list1[i]["VLAN"]] = i
# `indexes` now => {"500": 0, "600": 1, "700": 2}
for a in list2:
  # now it's easy to target the right `"OUI"` list
  # for example the first iteration
  # list1[0]["OUI"].append("0001FC")
  list1[indexes[a["VLAN"]]]["OUI"].append(a["OUI"])

print(list1)

输出：

[
  {'VENDOR': 'VENDOR1', 'VLAN': '500', 'OUI': ['0001FC', '00D024']},
  {'VENDOR': 'VENDOR2', 'VLAN': '600', 'OUI': ['00D024']},
  {'VENDOR': 'VENDOR3', 'VLAN': '700', 'OUI': ['00D024', '023456']}
]

Answer 2

执行该操作所需的代码在这里：

 for i in range(0,len(list1)):
      for j in range(0,len(list2)):
          if(list1[i]["VLAN"] == list2[j]["VLAN"]):
              list1[i]["OUI"].append(list2[j]["OUI"])

并使用以下代码测试是否有正确的输出：

 for i in range(0,len(list1)):
        print(list1[i]["OUI"])

我相信这段代码是不言自明的，但是如果您想解释为什么会这样，请随时询问。

Answer 3

我将list1重组为嵌套字典，其中VLAN为键，然后迭代list2并将VLAN项目添加到OUI嵌套字典中的列表。然后我们可以只打印嵌套字典的values()。

list1 = [
    {"VENDOR": "VENDOR1", "VLAN": "500", "OUI": []},
    {"VENDOR": "VENDOR2", "VLAN": "600", "OUI": []},
    {"VENDOR": "VENDOR3", "VLAN": "700", "OUI": []},
]

list2 = [
    {"VLAN": "500", "OUI": "0001FC"},
    {"VLAN": "600", "OUI": "00D024"},
    {"VLAN": "500", "OUI": "00D024"},
    {"VLAN": "700", "OUI": "00D024"},
    {"VLAN": "700", "OUI": "023456"},
]

vendors = {v["VLAN"]: v for v in list1}
# {'500': {'VENDOR': 'VENDOR1', 'VLAN': '500', 'OUI': []}, '600': {'VENDOR': 'VENDOR2', 'VLAN': '600', 'OUI': []}, '700': {'VENDOR': 'VENDOR3', 'VLAN': '700', 'OUI': []}}

for vlan in list2:
    vendors[vlan["VLAN"]]["OUI"].append(vlan["OUI"])

print(list(vendors.values()))

输出：

[{'VENDOR': 'VENDOR1', 'VLAN': '500', 'OUI': ['0001FC', '00D024']}, {'VENDOR': 'VENDOR2', 'VLAN': '600', 'OUI': ['00D024']}, {'VENDOR': 'VENDOR3', 'VLAN': '700', 'OUI': ['00D024', '023456']}]

Python3-比较两个字典的列表并更新值

3 个答案: