我有一个login.swift
,主要是:
import SwiftUI
class GlobalEnvironment: ObservableObject {
@Published var accountId: Int = 0
}
struct Login: View {
@EnvironmentObject var env: GlobalEnvironment
@State private var username: String = ""
@State private var password: String = ""
@State var authenticationDdidFail: Bool = false
@State var authenticationDidSucceed: Bool = false
var body: some View {
if env.accountId == 0 {
return AnyView(LoginView(username: self.$username, password: self.$password, authenticationDdidFail: self.$authenticationDdidFail, authenticationDidSucceed: self.$authenticationDidSucceed))
} else {
return AnyView(ContentView().environmentObject(GlobalEnvironment()))
}
}
}
...
在LoginView中成功登录后,文件也会设置env.accontId
。
然后我有一个data.swit
,其中:
struct Transaction: Codable, Identifiable {
let id = UUID()
var purpose: String
}
class Api {
@EnvironmentObject var env: GlobalEnvironment
func getTransactions(completion: @escaping ([Transaction]) -> ()) {
guard let url = URL(string: "https://url.com/api.php?get_transactions&account=\(env.accountId)") else { return }
URLSession.shared.dataTask(with: url) { (data, _, _) in
let transactions = try! JSONDecoder().decode([Transaction].self, from: data!)
DispatchQueue.main.async {
completion(transactions)
}
}
.resume()
}
从Transactions.swift
调用API:
import SwiftUI
struct ContentView: View {
@EnvironmentObject var env: GlobalEnvironment
@State var transactions: [Transaction] = []
var body: some View {
NavigationView {
List(transactions) { transaction in
Text(transaction.purpose)
}
.environmentObject(GlobalEnvironment())
.onAppear {
Api().getTransactions { (transactions) in
self.transactions = transactions
}
}
.navigationBarTitle(Text("Transactions"))
}
}
}
我收到Thread 1: Fatal error: No ObservableObject of type GlobalEnvironment found. A View.environmentObject(_:) for GlobalEnvironment may be missing as an ancestor of this view.
的错误guard let url = URL(string: "https://url.com/api.php?get_transactions&account=\(env.accountId)") else { return }
。
根据我的理解,将GlobalEnvironment添加到Api类中应该可以,但是不能。相反,我已经尝试将其添加到函数中,但是它都不起作用。如您所见,与将.environmentObject()添加到列表视图本身相同。
答案 0 :(得分:0)
必须为:
.environmentObject(self.env)
当然,在SceneDelegate或其他地方可能还会有其他错误。
答案 1 :(得分:0)
您能否在environmentObject
的通话中发送onAppear
.onAppear
{
Api().getTransactions { (transactions) in
self.transactions = transactions
}.environmentObject(self.env)
}