Question

所以我的代码可以完成我想要的事情，但是我敢肯定，有一种更短的方法可以做到，您可以立即获取与输入相关的价格。我只是不确定该怎么做，here是原始说明！

service1 = 'Oil change'
service2 = 'Tire rotation'
service3 = 'Car wash'

name1 = 'oil change'
name2 = 'tire rotation'
name3 = 'car wash'

price1 = 35
price2 = 19
price3 = 7

auto_service = input('Enter desired auto service:\n')

if auto_service in service1:
    print('You entered: {}'.format(service1))
    print('Cost of {}: ${}'.format(name1, price1))

elif auto_service in service2:
    print('You entered: {}'.format(service2))
    print('Cost of {}: ${}'.format(name2, price2))

elif auto_service in service3:
    print('You entered: {}'.format(service3))
    print('Cost of {}: ${}'.format(name3, price3))

else:
    print('You entered: {}'.format(auto_service))
    print('Error: Requested service is not recognized')

Answer 1

是的，使用带有服务价格对的字典。

services = {
    'oil change': 35,
    'tire rotation': 19,
    'car wash': 7,
    }

由于这是家庭作业，因此我将让您弄清楚如何实现它，但这是一个片段，至少可以帮助您入门：if auto_service.lower() in services:

Answer 2

prices = {
    'Oil change': 35,
    'Tire rotation': 19,
    'Car wash': 7,
}

service = input('Enter desired auto service: ')
print(f"You entered: {service}")
try:
    print(f"Cost of {service}: ${prices[service]}")
except KeyError:
    print(f"Error: requested service is not recognized")

Answer 3

services = ['Oil change', 'Tire rotation', 'Car wash']
prices = [35, 19, 7]

auto_service = input('Enter desired auto service:\n')

print("Cost:", prices[services.index(auto_service)])

您可以将数据存储在list中，并使用.index()从另一个列表中获取相应的值。

注意：如果您提供的值不在列表中，它将抛出ValueError。我将其保留为练习，以供您解决。

Answer 4

services = [ {'name': 'oil change',    'price': 35},
             {'name': 'tire rotation', 'price': 19},
             {'name': 'car wash',      'price': 7 } ]

auto_service = input('Enter desired auto service:\n')

for service in services:
    if auto_service.lower() in service['name']:
        print('You entered: {}'.format(service['name']))
        print('Cost of {}: ${}'.format(service['name'], service['price']))
        break

Answer 5

这是我的方法：-

service = ('Oil change','Tire rotation','Car wash')
name = ('oil change','tire rotation','car wash')
price = (35,19,7)
auto_service = input('Enter desired auto service:\n')
if auto_service in service:
    pos=service.index(auto_service)
    print('You entered: {}'.format(auto_service))
    print('Cost of {}: ${}'.format(name[pos], price[pos]))
else:
    print('You entered: {}'.format(auto_service))
    print('Error: Requested service is not recognized')

Answer 6

使用字典-并将数据存储在其中；您不需要每个项目3个变量-您只需一个变量。

Name

Answer 7

这是我为您解决的问题。此页面上的许多其他回复也不错。

if (calcValue == '1')
{
  calc.output.value += '1';
}
else if (calcValue == '2')
{
  calc.output.value += '2';
}
else if (calcValue == '3')
{
  calc.output.value += '3';
}

有什么方法可以缩短我的python代码？

7 个答案: