我有一个“开始”和“停止”按钮,并且当前状态为就绪或未就绪。 我想要的行为是:
按下开始按钮时状态尚未就绪,仅在按下停止按钮4秒钟后才处于就绪状态。如果在这4秒钟内按下启动按钮,我希望在停止功能将其设置为就绪后状态立即变为“未就绪”(因此本质上启动功能应等待停止功能完成)。
这是我尝试用来解决此问题的示例应用程序:
import 'package:flutter/cupertino.dart';
import 'package:flutter/material.dart';
void main() {
runApp(MyApp());
}
class MyApp extends StatelessWidget {
@override
Widget build(BuildContext context) {
return MaterialApp(
home: HomePage(),
);
}
}
class HomePage extends StatefulWidget {
@override
_HomePageState createState() => _HomePageState();
}
class _HomePageState extends State<HomePage> {
@override
Widget build(BuildContext context) {
return Scaffold(
body: Column(
crossAxisAlignment: CrossAxisAlignment.stretch,
mainAxisAlignment: MainAxisAlignment.center,
children: <Widget>[
Text(
isCurrentlyReady ? "ready" : "not ready",
textAlign: TextAlign.center,
),
if (canPressStart)
CupertinoButton(
child: Text('Start'),
onPressed: start,
)
else
CupertinoButton(
child: Text('Stop'),
onPressed: stop,
)
],
),
);
}
bool isCurrentlyReady = true;
bool canPressStart = true;
Future<bool> isReadyFuture = Future.value(true);
start() async {
setState(() {
canPressStart = false;
});
await isReadyFuture;
setState(() {
isCurrentlyReady = false;
});
//this future will never come
isReadyFuture = Future.delayed(Duration(days: 90000), () => true);
}
stop() async {
setState(() {
canPressStart = true;
});
await Future.delayed(Duration(seconds: 4));
setState(() {
isCurrentlyReady = true;
});
isReadyFuture = Future.value(true);
}
}
我如何实现期望的行为?
答案 0 :(得分:1)
您在这里:https://codepen.io/gazialankus/pen/NWGMYEe
SO也需要该代码。此处:
Object token;
bool isReady = false;
void onStart() {
setState(() {
isReady = false;
});
token = null;
}
Future<void> onStop() async {
Object myToken = Object();
token = myToken;
await Future.delayed(Duration(seconds: 4));
if (token == myToken) {
setState(() {
isReady = true;
});
token = null;
}
}