Question

我想检查unorderedPhrases数组中的所有音频文件名是否在包含URL的result数组中。如果都存在，则返回true，如果存在，则返回false。

这是我尝试过的。我不知道为什么它总是返回false！？

let result = [

  "https://example.com/test/unordered/i was sent to earth to protect you_A/i was sent.mp3",
  "https://example.com/test/unordered/i was sent to earth to protect you_A/to earth.mp3",
  "https://example.com/test/unordered/i was sent to earth to protect you_A/to protect you.mp3",

];

const unorderedPhrases = [

    'i was sent',
    'to earth',
    'to protect you'

];

function checkResults(){
	
    return unorderedPhrases.every(r=> result.includes(r));

 
}

console.log(checkResults())

上面的代码应该返回true，因为unorderedPhrases中的所有音频文件都存在于result数组中。

如果我们有此数组，则它应该返回false，因为unorderedPhrases中有一个项目在result中不存在：

let result = [
  "https://example.com/test/unordered/i was sent to earth to protect you_A/i was sent.mp3",
  "https://example.com/test/unordered/i was sent to earth to protect you_A/to earth.mp3",
];

Answer 1

如果您想忽略文件夹结构而只考虑最后的内容，可以先从每个result项目中删除文件夹部分，将其变成另一个数组，然后遍历短语，检查没有文件夹部分的数组是否包含短语加.mp3：

let result = [
  "https://example.com/test/unordered/i was sent to earth to protect you_A/i was sent.mp3",
  "https://example.com/test/unordered/i was sent to earth to protect you_A/to earth.mp3",
  "https://example.com/test/unordered/i was sent to earth to protect you_A/to protect you.mp3",
];

const resultWithoutFolders = result.map(str => str.split('/').pop());

const unorderedPhrases = [
  'i was sent',
  'to earth',
  'to protect you'
];

function checkResults() {
  return unorderedPhrases.every(
    phrase => resultWithoutFolders.includes(phrase + '.mp3')
  );
}

console.log(checkResults())

Answer 2

由于result是2D数组，因此返回false。这意味着您的result具有3个元素，即这3个字符串，每个字符串都是由字符组成的数组。

编辑：很抱歉您的错误假设。 T.J.人群为我指出了。它不是二维数组。字符串也像数组一样。因此可以像二维数组一样访问它

这将是一个更正确的代码段：

let result = [

  "https://example.com/test/unordered/i was sent to earth to protect you_A/i was sent.mp3",
  "https://example.com/test/unordered/i was sent to earth to protect you_A/to earth.mp3",
  "https://example.com/test/unordered/i was sent to earth to protect you_A/to protect you.mp3",

];

const unorderedPhrases = [

    'i was sent',
    'to earth',
    'to protect you'

];

function checkResults(){
	
    return unorderedPhrases.every(r => result[0].includes(r))

 
}

console.log(checkResults())

如果要检查result中的所有3个字符串，则必须对其进行循环。每次都像上面一样检查unorderedPhrases

检查数组的所有元素是否包含在另一个数组中

2 个答案: