我将有2个数组,如下所示。 combosArr 是2D数组, arr1 是整数数组
let combosArr = [[1,2,3], [3,6,9]];
let arr1 = [1,2,3,4,5,6,7]; // return [1,2,3]
如果combosArr
中存在每个元素的整数,我希望checker函数向我返回arr1
的元素(它是一个数组)。
我尝试了以下对我不起作用的代码。
let checker = (compareThis, combos) => {
combos.some(array => {
array.every(e => {
if (compareThis.includes(e)) console.log(array);
})
})
}
答案 0 :(得分:0)
此代码使窍门:
let combosArr = [[1,2,3], [3,6,7]];
let arr1 = [1,2,3,4,5,6,7];
combosArr.forEach(e => {
if(e.every(r => arr1.includes(r)))
console.log(e);
})
或以下情况,仅当combosArr中两个数组的所有元素都包含arr1的元素时,才打印某些内容:
let combosArr = [[1,2,3], [3,6,7]];
let arr1 = [1,2,3,4,5,6,7];
var count = 0;
combosArr.forEach(e => {
if(e.every(r => arr1.includes(r)))
count++;
})
if(count == combosArr.length)
console.log(combosArr);