在这样的简单情况下
function onSubmit() { e.preventDefault(); /* Some Submit Logic */ }
<form data-testid="form" onSubmit={(e) => onSubmit(e)}>
<button type="submit" data-testid="submit-button">Submit</button>
</form>
如何确保单击提交按钮时提交表单?
const { queryByTestId } = render(<LoginForm/>);
const LoginForm = queryByTestId("form")
const SubmitButton = queryByTestId("submit-button")
fireEvent.click(SubmitButton)
???
如何测试是否已调用onSubmit()或表单已提交?
答案 0 :(得分:0)
基本上,这是我“解决”的问题:
// LoginForm.js
export function LoginForm({ handleSubmit }) {
const [name, setName] = useState('');
function handleChange(e) {
setName(e.target.value)
}
return (
<form data-testid="form" onSubmit={() => handleSubmit({ name })}>
<input required data-testid="input" type="text" value={name} onChange={(e) => handleChange(e)}/>
<button type="submit" data-testid="submit-button">Submit</button>
</form>
)
}
export default function LoginPage() {
function handleSubmit(e) {
// submit stuff
}
return <LoginForm handleSubmit={(e) => handleSubmit(e)}/>
}
现在测试的文件:
// LoginForm.test.js
import React from 'react';
import { render, fireEvent } from "@testing-library/react";
import LoginPage, { LoginForm } from "./LoginPage";
it("Form can be submited & input field is modifiable", () => {
const mockSubmit = jest.fn();
const { debug, queryByTestId } = render(<LoginForm handleSubmit={mockSubmit}/>);
fireEvent.change(queryByTestId("input"), { target: { value: 'Joe Doe' } }); // invoke handleChange
fireEvent.submit(queryByTestId("form"));
expect(mockSubmit).toHaveBeenCalled(); // Test if handleSubmit has been called
expect(mockSubmit.mock.calls).toEqual([[{name: 'Joe Doe'}]]); // Test if handleChange works
});
答案 1 :(得分:0)
我建议使用 nock 拦截从表单发送的请求并在之后返回模拟响应。 例如:
nock('https://foo.bar').post('/sign-up', formValues).reply(201);
但我想知道更好的解决方案。