Question

我正在尝试使用pandas.df.to_excel（）方法创建一个Excel报告。这是我的片段。

r2 = [183, 143]

for item in r2:
    cursor.execute('select distinct Version_Num from dbo.test where CMS_ID = ? and deployment_status = 0', item)
    row3 = cursor.fetchall()
    thi_tuple = [c_tup[0] for c_tup in row3]
    r3 += list(map(int, thi_tuple))
    print(r3)
    df2 = DataFrame({'CMS_ID': item, 'version': r3})
    writer2 = ExcelWriter(join(sep, "C:" + sep, "MyCave" + sep, "iso" + sep, "SDG" + sep, "Int" + sep, "latest" + sep, "other_dependencies.xlsx"), engine = 'xlsxwriter')
    df2.to_excel(writer2, sheet_name = 'other dependencies', startrow=1, header=False )
    workbook  = writer2.book
    worksheet = writer2.sheets['other dependencies']
    for col_num, value in enumerate(df2.columns.values):
            worksheet.write(0, col_num + 1, value)
     writer2.save()

它正在写入Excel工作表。

不是将r2的两个项目都打印为excel，而是仅打印143。

如何解决逻辑？

致谢

Answer 1

我将您的代码更改为此：

r2 = [183, 143]

writer2 = ExcelWriter(os.path.join(sep, "tmp" + sep, "other_dependencies.xlsx"), engine = 'xlsxwriter')
for i in range(0, len(r2)):
    item = r2[i]  # the item here is equal to the item in "for item in r2:"
    cursor.execute('select distinct Version_Num from dbo.test where CMS_ID = ? and deployment_status = 0', item)
    row3 = cursor.fetchall()
    thi_tuple = [c_tup[0] for c_tup in row3]
    r3 += list(map(int, thi_tuple))
    print(r3)
    df2 = DataFrame({'CMS_ID': item, 'version': r3})
    df2.to_excel(writer2, sheet_name = 'other dependencies', startrow=i+1, header=False )
    workbook  = writer2.book
    worksheet = writer2.sheets['other dependencies']
    for col_num, value in enumerate(df2.columns.values):
            worksheet.write(0, col_num + 1, value)
writer2.save()

我将excel文件的创建移到了for循环的外部。而且我还将startrow更改为变量i。

i确定要写入的行。

startrow从1开始，而索引r2从0开始。这就是为什么我为i+1写startrow的原因。

熊猫to_excel是覆盖值

1 个答案: