Question

尝试使用urllib2.urlopen从youtube gdata api中提取数据时，收到HTTP 403错误。我已经关闭了CSRF中间件以进行调试，我正在使用的视图如下所示：

def videos (request):
    params = {}
    youtube_search_url = 'http://gdata.youtube.com/feeds/api/videos'
    params['order_by'] = 'relevance'
    params['max_results'] = 10
    params['safeSearch'] = 'strict'
    params['v'] = 2
    params['key'] = '<developer key>'
    f = urllib2.urlopen(youtube_search_url, encoded_params)
    ...

有什么想法吗？

Answer 1

When you make an API request, use the X-GData-Key request header to specify your developer key as shown in the following example:

X-GData-Key: key=<developer_key>

Include the key query parameter in the request URL.

http://gdata.youtube.com/feeds/api/videos?q=SEARCH_TERM&key=DEVELOPER_KEY

^^直接从马的嘴里出来。您缺少X-GData-Key请求标头。在网址和标题中似乎都需要密钥，因此根据您之前的代码，请尝试以下操作：

req = urllib2.Request(youtube_search_url, encoded_params, { "X-GData-Key": '<developer key>' })
f = urllib2.urlopen(req)

在Django视图中从gdata api中提取数据时获取HTTP 403

1 个答案: