Question

下午好，

我正在使用乌龟模拟病毒爆发。我想出了以下代码，我的问题将在代码之后：

import turtle
import random
import time

def make_population(amount):
    """
    Creates a list representing a population with a certain amount of people.
    """
    population = []
    for person in range(amount):
        population.append(turtle.Turtle())
    for person in population:
        person.shape("circle")
        person.shapesize(0.2)
    return population

def random_move(person):
    """
    Makes a turtle move forward a random amount and then turn a random amount.
    """
    person.forward(random.randint(0,20))
    person.right(random.randint(-180,180))

def check_boundary(person):
    """
    Checks if a turtle is still within the given boundaries.
    """
    if -250 <= person.xcor() <= 250 and -250 <= person.ycor() <= 250:
        return
    person.setpos(random.randint(-200,200),random.randint(-200,200))

def infect_random(population):
    """
    Gets a random item from the population list and turns one red
    """
    infected = random.choice(population)
    infected.color("red")
    return infected

def infect_person(person):
    """
    Makes the turtle infected
    """
    infected_person = person.color("red")
    return infected_person

def simulation(amount, moves = 0):
    """
    Simulates a virus outbreak
    """
    border = 500
    window = turtle.Screen()
    turtle.setup(500,500)
    turtle.tracer(0)
    population = make_population(amount)
    for person in population:
        person.penup()
        person.setpos(random.randint(-250,250),random.randint(-250,250))
    turtle.update()
    infected = infect_random(population)
    for move in range(moves):
        turtle.tracer(0)
        for person in population:
            random_move(person)
            if person.distance(infected) < 50:
                infect_person(person)
            check_boundary(person)
        turtle.update()
        time.sleep(0.5)

    window.exitonclick()

因此，当模拟开始时，我会感染1个随机人，并且如果其他乌龟靠近，例如在50像素之内，它们也会被感染并变红。但是，这些新感染的乌龟不会感染其他乌龟，因为与最初的乌龟相比，它们没有被“感染”。我尝试将其更改为感染= infect_person（person），但这给我一个错误。我现在停留了一段时间，想知道是否有人可以提供帮助。我还考虑过要列出两个列表：“人口”和“受感染的人群”也许可以解决我的问题，但是我不知道如何在其余的代码中实现它。

预先感谢

Answer 1

我认为解决方案是将低级乌龟操作从模拟中的人的高级别操作分为Person的{{1}}子类：

Turtle

我们可以进一步处理乌龟计时器事件，以使人们更加自主，而不是from turtle import Screen, Turtle from random import randint, choice from time import sleep class Person(Turtle): population = [] def __init__(self): super().__init__(shape='circle') self.shapesize(0.2) self.penup() self.setpos(randint(-250, 250), randint(-250, 250)) Person.population.append(self) @classmethod def all_infected(cls): return [person for person in cls.population if person.infected()] def infect(self): self.color('red') def infected(self): return self.pencolor() == 'red' def random_move(self): """ Makes a turtle move forward a random amount and then turn a random amount. """ self.right(randint(-180, 180)) self.forward(randint(0, 20)) # checks if turtle is still within the given boundaries. if not (-250 < self.xcor() < 250 and -250 < self.ycor() < 250): self.undo() # undo forward() def make_population(amount): """ Creates a list representing a population with a certain amount of people. """ for _ in range(amount): Person() def infect_random(): """ Gets a random item from the population list and turns one red """ person = choice(Person.population) person.infect() def simulation(amount=20, moves=100): """ Simulates a virus outbreak """ make_population(amount) infect_random() screen.update() for _ in range(moves): for person in Person.population: person.random_move() if not person.infected(): for infected in Person.all_infected(): if person.distance(infected) < 50: person.infect() screen.update() sleep(0.5) screen = Screen() screen.setup(500, 500) screen.tracer(0) simulation() screen.exitonclick()循环。

Answer 2

我相信您已经举了一个小例子，但是我们错过了有关数据结构的信息，人是一类吗？

您不要将其重新分配为受感染的人。

当您感染第一批人

infected = infect_random(population)

您将其指定为受感染，但是当您感染他人时，您不会您将其变成红色返回此人：

def infect_person(person):
    """
    Makes the turtle infected
    """
    infected_person = person.color("red")
    return infected_person

但是，母鸡在您的代码中没有分配它，

infect_person(person)

我建议您使用一种方式来了解谁被感染或未被感染。例如：如果您使用过POO：

您可以添加一个字段is_infected
还使用一个列表来保留被感染者的索引吗？

这样做，您将必须更改附近是否有人被感染的测试方式。对于一个人附近的所有人，如果有人被感染了，那么我就被感染了……

当一只乌龟靠近另一只乌龟时，我该怎么做？

2 个答案: