我正在使用Collections.sort()
按运行时顺序对MP3列表进行排序,如果运行时相等,则按标题按字母顺序排序,如果标题相等,则按作曲家排序。我将输入输入stdin
即
示例输入
3 & Pink Frost&Phillipps, Martin&234933 Se quel guerrier io fossi&Puccini, Giacomo&297539 Non piu andrai&Mozart&234933 M'appari tutt'amor&Flotow, F&252905
但是它没有通过输入提出任何东西。我很困惑,因为它应该完美。我没有任何错误。
public class Lab3Algorithm {
public static void main(String args[]) throws IOException {
List<Song> songs = new ArrayList<Song>();
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int numOfSongsRequired = Integer.parseInt(br.readLine());
String sep = br.readLine();
String line;
while((line = br.readLine()) != null) {
String[] fields = sep.split(line);
songs.add(new Song(fields[0], fields[1], fields[2]));
}
Collections.sort(songs);
System.out.println(songs);
}
}
public class Song implements Comparable<Song> {
private final String title;
private final String composer;
private final int runningTime;
public Song(String title, String composer, String runningTime) {
this.title = title;
this.composer = composer;
this.runningTime = Integer.parseInt(runningTime);
}
public String getTitle(){
return this.title;
}
public String getComposer(){
return this.composer;
}
public int getRunningTime(){
return this.runningTime;
}
@Override
public int compareTo(Song s) {
if (runningTime > s.runningTime) {
return 1;
} else if (runningTime < s.runningTime) {
return -1;
}
int lastCmp = title.compareTo(s.title);
return (lastCmp != 0 ? lastCmp : composer.compareTo(s.composer));
}
}
如果有人能指出我正确的方向,那会让我感激不尽。
答案 0 :(得分:3)
String[] fields = sep.split(line);
似乎错了 - 你不是试图在歌曲输入上拆分分隔符字符串;你想在分隔符上分割歌曲输入:
String[] fields = line.split(sep);
答案 1 :(得分:2)
你的错误
for(int i = 0;i<numOfSongsRequired ;i++) {
line = br.readLine();
String[] fields = line.split(sep);//line should be splitted by sep btw
songs.add(new Song(fields[0], fields[1], fields[2]));
}
如果有EOF(ctrl-z或ctrl-d取决于平台),readline仅给出null
否则它只会阻止等待下一行